sqlite3_open：“无法打开数据库文件”(sqlite3_open: “unable to

执行RC当= sqlite3_open（ “test.db的”，＆DB）我得到 “无法打开数据库文件”; ??

sqlite3 *db; // sqlite3 db struct
char *zErrMsg = 0;
int rc;

// Open the test.db file
rc = sqlite3_open("test.db", &db); // <-- creates DB if not found ??

if( rc ){
    // failed
    fprintf(stderr, "ERROR: Can't open database: %s\n", sqlite3_errmsg(db));
} 

Answer 1:

sqlite3_open如果数据库不存在返回错误。 要创建数据库，如果它不存在，使用sqlite3_open_v2与SQLITE_OPEN_CREATE和SQLITE_OPEN_READWRITE标志（ 两者都需要 ）：

rc = sqlite3_open_v2(/* DB Path */, &db, SQLITE_OPEN_CREATE | SQLITE_OPEN_READWRITE, NULL);

参考

---

要查找/* DB PATH */时，需要立足关名的文件目录：

- (NSString *) applicationDocumentsDirectory 
{    
    NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES);
    NSString *basePath = ([paths count] > 0) ? [paths objectAtIndex:0] : nil;
    return basePath;
}

您可以使用此便捷方法的文件路径和数据库名称相结合：

NSString *documents = [self applicationDocumentsDirectory];
NSString *dbPath = [documents stringByAppendingPathComponent:@"test.db"];

rc = sqlite3_open_v2([dbPath UTF8String], &db, SQLITE_OPEN_CREATE | SQLITE_OPEN_READWRITE, NULL);

Answer 2:

#define SQLITE_OK 0
sqlite3 *db;
char *zErrMsg=0;
if(sqlite3_open("demo.db", &db) == SQLITE_OK)
{
    if(sqlite3_exec(db, "select * from Users", callback, 0, &zErrMsg) == SQLITE_OK)
            msgbox1("success");
    sqlite3_close(db);
}
else
    msgbox1("failure");

这里是我使用的样本代码;

文章来源: sqlite3_open: “unable to open database file”