SQL行之和为某些colums(SQL Row Sum for some colums)

2019-09-18 09:18发布

我试图开发一个SQL字段是除前两行的所有列的总和。 下面是我的代码,它返回MonthYear,道达尔,SUM1,SUM2,并SUM3列。 我想有哪些共计SUM1,SUM2,并SUM3一个FinalSum。 这是用来对付检查总计列的准确性。 有没有办法做到这一点? 运行Microsoft SQL Server 2005 - T-SQL

SELECT MonthYear,
            COUNT(*) AS Total,
            ISNULL(
                SUM(
                    CASE 
                    WHEN Status='Sum1'                  THEN 1
                    ELSE 0
                    END
                )
            ,0) AS [Sum1],
ISNULL(
                SUM(
                    CASE 
                    WHEN Status='Sum2'                  THEN 1
                    ELSE 0
                    END
                )
            ,0) AS [Sum2],
ISNULL(
                SUM(
                    CASE 
                    WHEN Status='Sum3'                  THEN 1
                    ELSE 0
                    END
                )
            ,0) AS [Sum3]
FROM tablename

GROUP BY
    MonthYear

Answer 1:

你是缺少FROM您的查询。 无论是哪种方法将使用派生表:

SELECT *, [Sum1]+[Sum2]+[Sum3] AS TotalSum
FROM (Your Current Select Here) AS T

对于SQL Server 2005 +,你也可以用热膨胀系数:

;WITH CTE AS 
(
    Your Current Select Here
)
SELECT *, [Sum1]+[Sum2]+[Sum3] AS TotalSum
FROM CTE


Answer 2:

好了-可能不是最优雅的方式(复印件保存在这里的SqlFiddle )

CREATE TABLE this_name 
(
    monthYear DateTime,
    status varchar(20), 
   );

INSERT INTO this_name
(monthYear, status)
VALUES
('01 jan 2012', 'Sum1'),
('01 jan 2012', 'Sum1'),
('01 feb 2012', 'Sum2'),
('01 feb 2012', 'Sum1'),
('01 apr 2012', 'Sum3'),
('01 jan 2013', 'Sum3'),
('01 jan 2013', 'Sum3'),
('01 jan 2012', 'Sum3')

;WITH myCTE (MonthYear,Total, Sum1, Sum2, Sum3)
AS
(
SELECT MonthYear,
       COUNT(*) AS Total,
       SUM(CASE WHEN ISNULL(Status,'X')='Sum1' THEN 1 ELSE 0 END) AS [Sum1],
       SUM(CASE WHEN ISNULL(Status,'X')='Sum2'THEN 1 ELSE 0 END ) AS [Sum2],
       SUM(CASE WHEN ISNULL(Status,'X')='Sum3' THEN 1 ELSE 0 END) AS [Sum3] 
FROM this_name
GROUP BY MonthYear
)   
SELECT 
  MonthYear,
  Total, 
  Sum1, 
  Sum2, 
  Sum3,
  (Sum1 + Sum2 + Sum3) [CountTotal]
FROM myCTE

另一种选择是这一个( [SQLFiddle] ;

SELECT MonthYear,
   COUNT(*) AS Total,
   SUM(CASE WHEN ISNULL(Status,'X')='Sum1' THEN 1 ELSE 0 END) AS [Sum1],
   SUM(CASE WHEN ISNULL(Status,'X')='Sum2'THEN 1 ELSE 0 END ) AS [Sum2],
   SUM(CASE WHEN ISNULL(Status,'X')='Sum3' THEN 1 ELSE 0 END) AS [Sum3], 

   SUM(CASE WHEN ISNULL(Status,'X')IN('Sum1','Sum2','Sum3') THEN 1 ELSE 0 END) AS [SumExtra]  
FROM this_name
GROUP BY MonthYear


Answer 3:

declare @sum1 int, @sum2 int, @sum3 int
declare @totalSum int = 0

select @sum1 = ISNULL(SUM(CASE WHEN Status='Sum1' THEN 1 ELSE 0 END), 0)
from tablename

select @sum2 = ISNULL(SUM(CASE WHEN Status='Sum2' THEN 1 ELSE 0 END), 0)
from tablename

select @sum3 = ISNULL(SUM(CASE WHEN Status='Sum3' THEN 1 ELSE 0 END), 0)
from tablename

set @totalSum = @sum1 + @sum2 + @sum3

SELECT MonthYear, COUNT(*) AS Total,
            ISNULL(SUM(
                    CASE 
                    WHEN Status='Sum1' THEN 1
                    ELSE 0
                    END
                ), 0) AS [Sum1],
            ISNULL(SUM(
                    CASE 
                    WHEN Status='Sum2' THEN 1
                    ELSE 0
                    END), 0) AS [Sum2],
            ISNULL(SUM(
                    CASE 
                    WHEN Status='Sum3' THEN 1
                    ELSE 0
                    END), 0) AS [Sum3],
            @totalSum
FROM tablename

GROUP BY
    MonthYear


Answer 4:

使用临时表的一种方法

CREATE TABLE #Table2
(
    MonthYear VARCHAR(6) NOT NULL PRIMARY KEY,
    Total INT NOT NULL,
    Sum1 INT NOT NULL,
    Sum2 INT NOT NULL,
    Sum3 INT NOT NULL
) ;

INSERT INTO #Table2
SELECT
        MonthYear,
        COUNT(*) AS Total,
        SUM(CASE WHEN ISNULL(Status, '') = 'Sum1' THEN 1 ELSE 0 END),
        SUM(CASE WHEN ISNULL(Status, '') = 'Sum2' THEN 1 ELSE 0 END),
        SUM(CASE WHEN ISNULL(Status, '') = 'Sum3' THEN 1 ELSE 0 END)
FROM tablename
GROUP BY MonthYear ;

SELECT *, Sum1Count + Sum2Count + Sum3Count AS FinalSum FROM #Table2 ;


Answer 5:

具有重复的计算的另一种方法

SELECT
        MonthYear,
        COUNT(*) AS Total,
        SUM(CASE WHEN ISNULL(Status, '') = 'Sum1' THEN 1 ELSE 0 END) AS [Sum1],
        SUM(CASE WHEN ISNULL(Status, '') = 'Sum2' THEN 1 ELSE 0 END) AS [Sum2],
        SUM(CASE WHEN ISNULL(Status, '') = 'Sum3' THEN 1 ELSE 0 END) AS [Sum3],
        SUM(CASE WHEN ISNULL(Status, '') = 'Sum1' THEN 1 ELSE 0 END) +
        SUM(CASE WHEN ISNULL(Status, '') = 'Sum2' THEN 1 ELSE 0 END) +
        SUM(CASE WHEN ISNULL(Status, '') = 'Sum3' THEN 1 ELSE 0 END) AS [FinalSum]
FROM tablename
GROUP BY MonthYear ;


文章来源: SQL Row Sum for some colums