我有以下的LINQ代码
var q = (from web in DataContext.Webs select web);
List<int?> k1 = new List<int?>() { 1, 2 };
List<int?> k2=new List<int?>() { 16, 17 };
q = q.Where(web => DataContext.WebTechMaps.Any(t => t.WebsiteId == web.WebsiteId && k1.Contains(t.TechId)));
System.Diagnostics.Debug.WriteLine(q.Count());
k1 = k2;
q = q.Where(web => DataContext.WebTechMaps.Any(t => t.WebsiteId == web.WebsiteId && k1.Contains(t.TechId)));
System.Diagnostics.Debug.WriteLine(q.Count());
以下是查询它产生。
计数的第一次执行。
SELECT COUNT(*) AS [value]
FROM [dbo].[Web] AS [t0]
WHERE EXISTS(
SELECT NULL AS [EMPTY]
FROM [dbo].[WebTechMap] AS [t1]
WHERE ([t1].[WebsiteId] = ([t0].[WebsiteId])) AND ([t1].[TechId] IN (@p0, @p1))
)
-- @p0: Input Int (Size = -1; Prec = 0; Scale = 0) [1]
-- @p1: Input Int (Size = -1; Prec = 0; Scale = 0) [2]
计数功能的第二次执行
SELECT COUNT(*) AS [value]
FROM [dbo].[Web] AS [t0]
WHERE (EXISTS(
SELECT NULL AS [EMPTY]
FROM [dbo].[WebTechMap] AS [t1]
WHERE ([t1].[WebsiteId] = ([t0].[WebsiteId])) AND ([t1].[TechId] IN (@p0, @p1))
)) AND (EXISTS(
SELECT NULL AS [EMPTY]
FROM [dbo].[WebTechMap] AS [t2]
WHERE ([t2].[WebsiteId] = ([t0].[WebsiteId])) AND ([t2].[TechId] IN (@p2, @p3))
))
-- @p0: Input Int (Size = -1; Prec = 0; Scale = 0) [16]
-- @p1: Input Int (Size = -1; Prec = 0; Scale = 0) [17]
-- @p2: Input Int (Size = -1; Prec = 0; Scale = 0) [16]
-- @p3: Input Int (Size = -1; Prec = 0; Scale = 0) [17]
请看看传递给查询参数。
似乎它使用两个表达式的新引用的对象。
不知怎的,@ p0和@ P1改变自己的旧值。 据我所知,问题是Linq中它采用新的引用对象。
-- @p0: Input Int (Size = -1; Prec = 0; Scale = 0) [1]
-- @p1: Input Int (Size = -1; Prec = 0; Scale = 0) [2]
-- @p0: Input Int (Size = -1; Prec = 0; Scale = 0) [16]
-- @p1: Input Int (Size = -1; Prec = 0; Scale = 0) [17]
-- @p2: Input Int (Size = -1; Prec = 0; Scale = 0) [16]
-- @p3: Input Int (Size = -1; Prec = 0; Scale = 0) [17]
有人能解释如何使用List对象的名称相同,但采用正确的列表的保留查询
所需的输出是
-- @p0: Input Int (Size = -1; Prec = 0; Scale = 0) [1]
-- @p1: Input Int (Size = -1; Prec = 0; Scale = 0) [2]
-- @p2: Input Int (Size = -1; Prec = 0; Scale = 0) [16]
-- @p3: Input Int (Size = -1; Prec = 0; Scale = 0) [17]
提前致谢