Load page on selection from dropdown form

问题:

I am trying to make a drop down menu that takes me to various webpages. Right now it is set up so you make your selection and then you hit a "Go" button and then it takes you to the appropriate link. I am trying to figure out how to make it so when you make your selection it automatically goes and you don't need to push the "Go" button.

Here is what I have:

<p align="center">
<form name="jump" class="center">
<select name="menu">
<option value="#">Select an option</option>
<option value="/link1.shtml">Link 1</option>
<option value="/link2.shtml">Link 2</option>
<option value="/link3.shtml">Link 3</option>
</select>
<input type="button" onClick="location=document.jump.menu.options[document.jump.menu.selectedIndex].value;" value="GO">
</form>
</p>

Any help or links to explanations would be great. Thank you!

回答1:

Try the following:

<select onchange="location = this.options[this.selectedIndex].value;">
    <option>Please select</option>
    <option value="http://www.apple.com/">Apple</option>
    <option value="http://www.bbc.com">BBC</option>
    <option value="http://www.facebook.com">Facebook</option>
</select>​

What you were looking for was 'onchange' instead of 'onsumbit'

回答2:

Check out jQuery .change()

<script>
   $('select.menu').change(function(e){
      // this function runs when a user selects an option from a <select> element
      window.location.href = $("select.menu option:selected").attr('value');
   });
</script>

回答3:

Something like this might help - basically you just tie an onChange event to the select so that when a new option is selected it'll forward the location to the page.

<p align="center">
<form name="jump" class="center">
<select name="menu" onchange="gotoPage(this)">
<option value="#">Select an option</option>
<option value="/link1.shtml">Link 1</option>
<option value="/link2.shtml">Link 2</option>
<option value="/link3.shtml">Link 3</option>
</select>
<input type="button" onClick="location=document.jump.menu.options[document.jump.menu.selectedIndex].value;" value="GO">
</form>
</p>

<script type="text/javascript">
function gotoPage(select){
    window.location = select.value;
}
</script>

回答4:

I would recommend that you start using the javascript framework jQuery as it really will make your life much easier when it comes to javascript.

When you have jQuery installed and setup in you web page you should be able to do something like this:

<script type="text/javascript">
    $(document).ready(function() {
        $("#selection").change(function() {
            location = $("#selection option:selected").val();
        });
    });
</script>

<p align="center">
    <form name="jump" class="center">
        <select name="menu" id="selection>
            <option value="#">Select an option</option>
            <option value="/link1.shtml">Link 1</option>
            <option value="/link2.shtml">Link 2</option>
            <option value="/link3.shtml">Link 3</option>
        </select>
    </form>
</p>

回答5:

Obviously super late to the party here, but since I was trying to figure out the same thing and was able to, I'll post how here.

The other answers have you load the link when you change your select element option, but you originally had asked to do it with a button, after making your selection. This worked for me:

<script type="text/javascript">
    $(document).ready(function() {
        var newUrl = "";
        $("#picksite").change(function() {
            $newUrl = $("#picksite option:selected").val();
        });
        $("#executelink").click(function() {
            location = $newUrl ;
        });
    });
</script>

<select id="picksite">
    <option value="">Pick A Website</option>
    <option value="http://google.com">Google</option>
    <option value="http://facebook.com">Facebook</option>
    <option value="http://twitter.com">Twitter</option>
    <option value="http://gmail.com">Gmail</option>
</select>

<button id="executelink">Go To Site</button>