My intention with the below code is display the difference between two timestamps in seconds, but nothing is showing at all. I´ve added echo $ts for you to see what $ts contains:
$ts = $value['time'];
echo $ts;
$sql = "SELECT TIMESTAMPDIFF(SECOND,(CURRENT_TIMESTAMP),'$ts')";
$diff = mysql_query($sql);
echo $diff;
The result is:
2017-01-26 16:30:51
Hence it only shows the content of $ts, not what the time difference is. Help with understanding what I´m doing wrong would be appreciated, thanks!
mysql_query() function returns:
For SELECT, SHOW, DESCRIBE, EXPLAIN and other statements returning resultset, mysql_query() returns a resource on success, or FALSE on error.
For other type of SQL statements, INSERT, UPDATE, DELETE, DROP, etc, mysql_query() returns TRUE on success or FALSE on error.
The returned result resource should be passed to mysql_fetch_array(), and other functions for dealing with result tables, to access the returned data.
So you can try the following:
$con = mysql_connect("localhost", "root", "mypass") or
die("Could not connect: " . mysql_error());
mysql_select_db("tutorials");//**your database name**//
$sql = "SELECT TIMESTAMPDIFF(SECOND,(CURRENT_TIMESTAMP),'$ts') as timestamp";
$result = mysql_query($sql);
while ($row = mysql_fetch_array($result, MYSQL_NUM)) {
printf("diff: %s", $row[0]);
}
mysql_close($con);
Using Php only.
$datetime1 = strtotime($ts);
$datetime2 = strtotime(date('Y-m-d H:i:s'));
$interval = abs($datetime2 - $datetime1);
echo 'Diff. in seconds is: '.$interval;