Here is my code, it is really simple:
bif="C:\\Users\\Andrew\\Pictures\\pygame pictures\\Background(black big).png"
import pygame, sys
from pygame.locals import *
pygame.init()
screen=pygame.display.set_mode((1000,1000),0,32)
background=pygame.image.load(bif).convert()
line=pygame.draw.line(background, (255,255,255), (30,31), (20,31))
while True:
mousex, mousey = pygame.mouse.get_pos()
for event in pygame.event.get():
if event.type == QUIT:
pygame.quit()
sys.exit()
screen.blit(background, (0,0))
screen.blit(line,(mousex,mousey))
pygame.display.update()
The goal of this is to have the line follow my mouse on the screen. However, whenever I try to run the program I get the error :
TypeError: argument 1 must be pygame.Surface, not pygame.Rect
What does this mean, and what am I doing wrong?
The error means that it is expecting a surface not a rectangle. This is the offending line:
screen.blit(line,(mousex,mousey))
The problem is that you are assigning the result of draw.line() to line.
line=pygame.draw.line(background, (255,255,255), (30,31), (20,31))
From the pygame docs:
All the drawing functions respect the clip area for the Surface, and
will be constrained to that area. The functions return a rectangle
representing the bounding area of changed pixels.
So you are assigning a rectangle to line. Not sure exactly what you want to do, but you can draw the line following the mouse in the following way:
pygame.draw.line(background, (255,255,255), (x,y), (x,y+10))
You use pygame.draw.line wrong. You seem under the impression this returns a new image with the line drawn on background. It doesn't. It will modify the background image.
So instead, you should
- create a new surface "line" with the required dimensions, and full transparency
- draw your line on that surface
- use this then, not the return-value of pygame.draw.line
