I have a bash script that run a remote awk command but I guess I haven't correctly escape specials characters since no file is generated on the remote server. Still I have no error.
My variables are declared locally and can be used remotely without issue (other part of the script confirm this).
ssh -q -t server '
logfiles=$(find /var/log/httpd/ -type f -name *access_log -cmin -'"$past"')
for log in $logfiles;
awk -vDate=\`date -d'now-'"$past"' minutes' +[%d/%b/%Y:%H:%M:%S\` ' { if \(\$4 > Date\) print \$0}' $log | sort |uniq -c |sort -n | tail | cut -d " " -f 11,15,16
done
'
Thank you!
EDIT1:
passing this script
#!/bin/bsh
logfiles=$(find /var/log/httpd/ -type f -name *access_log -cmin -120)
for log in $logfiles; do
awk -vDate=`date -d'now-120 minutes' +[%d/%b/%Y:%H:%M:%S` ' { if ($4 > Date) print $0}' $log | sort |uniq -c |sort -n | tail | cut -d " " -f 11,15,16 > /root/httpd.log;
done
like this works
ssh user@host < script.sh
When I run the same script from the console :
ssh -q -t $apache '
logfiles=$(find /var/log/httpd/ -type f -name *access_log -cmin -120)
for log in $logfiles; do
awk -vDate=`date -d'now-120 minutes' +[%d/%b/%Y:%H:%M:%S` ' { if ($4 > Date) print $0}' $log | sort |uniq -c |sort -n | tail | cut -d " " -f 11,15,16 > /root/httpd.log;
done'
-bash: syntax error near unexpected token `('
So I tried to escape the parenthesis
ssh -q -t $apache '
logfiles=$(find /var/log/httpd/ -type f -name *access_log -cmin -120)
for log in $logfiles; do
awk -vDate=`date -d'now-120 minutes' +[%d/%b/%Y:%H:%M:%S` ' { if \($4 > Date\) print $0}' /var/log/httpd/royalcanin_com.access_log | sort |uniq -c |sort -n | tail | cut -d " " -f 11,15,16 > /root/httpd.log;
done'
but then nothing is generated.
EDIT2:
Having the file generated on the server but empty with this:
awk -vDate=\`date -d'now-120 minutes' +[%d/%b/%Y:%H:%M:%S\` ' { if '"($4 > Date)"' print $0}' $log | sort |uniq -c |sort -n | tail | cut -d " " -f 11,15,16 > /root/httpd.log;done'