How to compile without warnings being treated as e

问题:

The problem is that the same code that compiles well on Windows, is unable to compile on Ubuntu. Every time I get this error:

cc1: warnings being treated as errors

Now, it's big code base and I don't like fix all the warnings.

Is there any way I can compile successfully in spite of the warnings?

回答1:

Sure, find where -Werror is set and remove that flag. Then warnings will be only warnings.

回答2:

You can make all warnings being treated as such using -Wno-error. You can make specific warnings being treated as such by using -Wno-error=<warning name> where <warning name> is the name of the warning you don't want treated as an error.

If you want to entirely disable all warnings, use -w (not recommended).

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Source: http://gcc.gnu.org/onlinedocs/gcc-4.3.2/gcc/Warning-Options.html

回答3:

If you are compiling linux kernel. For example, if you want to disable the warning that is "unused-but-set-variable" been treated as error. You can add a statement:

KBUILD_CFLAGS += $(call cc-option,-Wno-error=unused-but-set-variable,)

in your Makefile

回答4:

Thanks for all the helpful suggestions. I finally made sure that there are no warnings in my code, but again was getting this warning from sqlite3:

Assuming signed overflow does not occur when assuming that (X - c) <= X is always true

which I fixed by adding the following CFLAG:

-fno-strict-overflow

回答5:

Remove -Werror from your Make or CMake files, as suggested in this post

回答6:

-Wall and -Werror compiler options can cause it, please check if those are used in compiler settings.