When I package my program into an exe using py2exe and try to run it, it comes back with the following:
Traceback (most recent call last):
File "raman_utility_v1.0.2.pyw", line 386, in <module>
File "raman_utility_v1.0.2.pyw", line 132, in __init__
File "raman_utility_v1.0.2.pyw", line 136, in getHome
File "subprocess.pyc", line 566, in check_output
File "subprocess.pyc", line 710, in __init__
File "subprocess.pyc", line 958, in _execute_child
WindowsError: [Error 2] The system cannot find the file specified
Currently my setup.py looks like this:
from distutils.core import setup
import py2exe
setup(
options={
"py2exe" : {"includes" : ["sip","subprocess"]}
},
windows=[{
"script" : "raman_utility_v1.0.2.pyw"
}]
)
And to run the setup.py, I run the following cmd:
python setup.py py2exe --includes sip
I have tried adding subprocess to the cmd like this:
python setup.py py2exe --includes sip,subprocess
but all that did was break sip.
I tried just copying the subprocess.pyc file into the dist folder, and that did not work. The last thing I tried was a suggestion from: py2exe not including the modules from "includes" which was to use "packages" instead of "includes" (for subprocess). That did not change anything. I also tried adding the line:
import subprocess
at the beginning of setup.py but that did not change anything either
Am I even on the right track? Any hints you have would be really helpful!