I've got a .dat file:
#id|firstName|lastName|gender|birthday|creationDate|locationIP|browserUsed
933|Mahinda|Perera|male|1989-12-03|2010-03-17T13:32:10.447+0000|192.248.2.123|Firefox
1129|Carmen|Lepland|female|1984-02-18|2010-02-28T04:39:58.781+0000|81.25.252.111|Internet Explorer
4194|Hồ Chí|Do|male|1988-10-14|2010-03-17T22:46:17.657+0000|103.10.89.118|Internet Explorer
8333|Chen|Wang|female|1980-02-02|2010-03-15T10:21:43.365+0000|1.4.16.148|Internet Explorer
8698|Chen|Liu|female|1982-05-29|2010-02-21T08:44:41.479+0000|14.103.81.196|Firefox
8853|Albin|Monteno|male|1986-04-09|2010-03-19T21:52:36.860+0000|178.209.14.40|Internet Explorer
10027|Ning|Chen|female|1982-12-08|2010-02-22T17:59:59.221+0000|1.2.9.86|Firefox
I want to take firstName, lastName and birthday from a specific line by id.
Example: if the input is 933, I want to extract (separated by space):
Mahinda Perera 1989-12-03
This should do it:
#!/bin/sh
id="$1"
awk -F '|' -v ID="$id" '($1==ID){print $2, $3, $5}' infile
Use as:
$ script.sh 933
Mahinda Perera 1989-12-03
awk -F'|' '$1 ~ /933/{print $2, $3, $5}' file
Mahinda Perera 1989-12-03
If field one matches 933 print following fields: 2,3 and 5.
With GNU sed:
$ id=933
$ sed -n "/^$id"'|/{s/^[^|]*|\([^|]*\)|\([^|]*\)|[^|]*|\([^|]*\)|.*$/\1 \2 \3/p;q}' infile
Mahinda Perera 1989-12-03
-n prevents printing; the rest does this:
"/^$id"'|/ { # If a line starts with the ID... (notice quoting for parameter expansion)
# Capture second, third and fifth field, discard rest, print
s/^[^|]*|\([^|]*\)|\([^|]*\)|[^|]*|\([^|]*\)|.*$/\1 \2 \3/p
q # Quit to avoid processing the rest of the file for nothing
}'
To get this to run under BSD sed, there has to be another semicolon between the q and the closing brace.
Goes to show that awk is much better suited for the problem.
Use:
awk '{print $2 $3 $5}' infile.dat
