I've come to the conclusion after reading from many sources that using printStackTrace
for error handling is bad practice. Here's one.
Now I'm struck curious: in what cases is printing the stacktrace a valid solution? For the sake of the argument, let's assume we aren't working on a system such as a microwave or a banana, but a basic out-of-the-shelf PC.
The reason I'm asking this could be seen as a question in itself, but I'll tell you about it anyhoo:
I'm developing a snake-like game that can be played with AIs, and is intended for that purpose. All such AIs should extend an abstract class called SnakeLogic
. All such AIs should also reside in their standalone .jar archives in a specific folder, from where the main program can find them and list them using classloaders.
The user can then choose one of his/her AIs from a list, should all stars fall in line, and play a game with this AI.
Now, I have a method in my main program that gets the next move from the AI like so:
public void startGame(int speed) {
gameInterface.showWindow();
Runnable moveCmd = () -> {
try {
for (Player player : snakeGame.getPlayers()) {
if (player.isDead()) {
continue;
}
String move = player.getLogicHandler().getMove();
Direction direction = Direction.directionFromString(move);
snakeGame.makeMove(player, direction);
}
gameInterface.getFrame().repaint();
snakeGame.wait(speed);
if (snakeGame.gameOver()) {
stopGame();
}
} catch (Exception ex) {
ex.printStackTrace();
stopGame();
}
};
/* moveSchedule is an instance of ScheduledExecutorService */
moveSchedule.scheduleAtFixedRate(moveCmd, 1000, speed, TimeUnit.MILLISECONDS);
}
I'm not going to get too involved with the code above. I'd like to draw your attention to the try-catch statement, however. As you can see I print the stacktrace and end the game, should an exception occur somewhere during the execution of the moveCmd
runnable. This is the source of my curiosity: If I don't print the stacktrace like this, or if I remove the try-catch entirely, I never get any errors in the case of a runtime exception during the execution of that block. Why? Is it because it's wrapped inside the runnable? Note also that the line snakeGame.makeMove(player, direction);
doesn't call any code in the main program; snakeGame is an instance of a SnakeLogic
, which resides in an external .jar.
Why don't I get any errors if I remove the try-catch? Also, in this case, is printing the stacktrace a good idea?
I understand this imposes two questions for you: the topic and the above. I want to emphasize the topic, so don't get too sidetracked with the second question; though insight is duly noted, there's nothing broken in my code.