ERROR 1055 (42000): Expression #1 of SELECT list i

问题:

This question already has an answer here:

• Retrieving the last record in each group - MySQL 24 answers

I am using MYSQL 5.7. I want to get the recent rows with distinct device_id. I tried these queries:

Query 1

SELECT `table`.`id`, `table`.`device_id` FROM `table` WHERE (id IN (SELECT id FROM (SELECT * FROM table ORDER BY date_modified DESC) AS last_modified GROUP BY device_id) and device_id <> '');

+----+------------------+
| id | device_id        |
+----+------------------+
|  5 | ffcecafe5eed4fba |
|  6 | ffcecafe5eed4fba |
|  8 | 71085f00e527bae0 |
+----+------------------+
3 rows in set (0.00 sec)

But it's not removing the duplicates.

SubQuery 1

SELECT id FROM (SELECT * FROM table ORDER BY date_modified DESC) AS last_modified GROUP BY device_id;
ERROR 1055 (42000): Expression #1 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'last_modified.id' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by

This gave error. Then I found on MySQL website to use ANY_VALUE() to remove this error.

SubQuery 2

SELECT ANY_VALUE(id) FROM (SELECT * FROM table ORDER BY date_modified DESC) AS last_modified GROUP BY device_id;
+---------------+------------------+
| ANY_VALUE(id) | device_id        |
+---------------+------------------+
|             7 |                  |
|             8 | 71085f00e527bae0 |
|             5 | ffcecafe5eed4fba |
+---------------+------------------+
3 rows in set (0.00 sec)

This is giving distinct ids. But when I am using ANY_VALUE in query 1 above, its giving the same result.

How to query distinct recent rows in MySQL 5.7 ?

---

Possible Duplicate

MySQL 5.7 return all columns of table based on distinct column

回答1:

This is the query that worked for me-

SELECT m1.*
FROM messages m1 LEFT JOIN messages m2
 ON (m1.name = m2.name AND m1.id < m2.id)
WHERE m2.id IS NULL;

Thanks @Shadow for the link to the possible duplicate.