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问题:
Is it possible to use blade @if conditions in functions of controller. This is my function of PublicController
public function tourBanner($country){
@if( $country == 'country1')
background-image:url({{ asset('images/inside8.jpg') }});
@elseif ( $country == 'country2')
background-image:url({{ asset('images/inside7.jpg') }});
@elseif ( $country == 'country3')
background-image:url({{ asset('images/inside5.jpg') }});
@elseif ( $country == 'country4')
background-image:url({{ asset('images/inside6.jpg') }});
@else
background-image:url({{ asset('images/inside10.jpg') }});
@endif
return banner;
}
And i'm getting this error
Parse error: syntax error, unexpected 'if' (T_IF)
What mistake i have made or we can't use blade if if statements in controller ?
回答1:
The syntax of Blade @if
is made for using in blade views not into the php files (as in your case controllers). You should use Blade Syntax in to files ending with extension - filename.blade.php, and in you controller please use normal PHP syntax for if statement.
Please see Blade Docs
class Controller {
function a() {
if($country == 'country1') {
$asset_str = asset('images/inside8.jpg');
$banner = "background-image:url({$asset_str})";
}
....
return $banner;
}
}
Hope this helps!
回答2:
Typos within your code that code is meant for blade files and not for your PHP files. Listing issues within your code
Remove @
from your code
@if .... @elsif
should be
if .... elseif
better for multiple if ... else
you can use switch case
You were returning banner
but it should be $banner
and also you were not assigning any value to $banner
variable. So your code be like as
if( $country == 'country1')
$banner = "background-image:url(".asset('images/inside8.jpg') .")";
.......
return $banner;
better to use switch case
like as
switch($country)
{
case "country1":
$banner = "background-image:url(".asset('images/inside8.jpg') .")";
break;
case ..............
}
回答3:
In controller you should write like this:
if ($country == 'country1') {
$a = 'background-image:url('.asset('images/inside8.jpg').')';
} elseif ....
But if you're gonna to build HTML/CSS/JS with PHP, it's terrible idea, do not do that.
回答4:
You could build up the style within your controller and then pass the resulting data to your view from that Controller and then render it. This snippet may give you a little insight:
<?php
public function tourBanner($country){
$extraData = ['zero', 'one', 'two'];
switch($country){
case 'country1':
$bgImage = 'images/inside8.jpg';
break;
case 'country2':
$bgImage = 'images/inside7.jpg';
break;
case 'country3':
$bgImage = 'images/inside5.jpg';
break;
case 'country4':
$bgImage = 'images/inside6.jpg';
break;
default:
$bgImage = 'images/inside10.jpg';
break;
}
return view("your.blade.view", array(
"bgImage" => $bgImage,
'extraData' => $extraData,
));
}
Then; in the View, it would be a matter of doing something like this:
<div class="container" style="background-image:url({{ asset($bgImage) }})">
<div class="col-md-12">
Some Content...
</div>
</div>
回答5:
Please try switch case for above condition.
switch ($country) {
case "country1":
echo "background-image:url({{ asset('images/inside8.jpg') }})";
break;
}
It will return exactly the same results.
回答6:
NO, you cant. just use the default if else
condition in php.
回答7:
Blade is a template parser, which converts code to PHP behind the scenes.
If you want to use some if statement in your controller you just use the standard IF statement.
if($q == $a) {
#more code here
} else {
$other code here
}
As suggested above, it's recommended using a switch statement when using a lot of else statements for your if
switch($q){
case "yes":
return $something;
break;
case "no":
return $somethingelse;
break;
case "maybe":
return $whoknows;
break;
}