Correct Condition For Window.External.Notify is De

问题:

I'm developing hybrid application that require to call window.external.notify in javascript but this js code should run in browser also. So we have to have a condition for detecting is window.external.notify is defined or undefined. So we use that code but in runtime window.external.notify shows its value is like that {...} (but can't open). Are there any way to handle it?

if(window.external !== undefined && window.external.notify !== undefined)

回答1:

You can use this:

if (typeof (window.external) !== 'undefined' && ('notify' in window.external)) {
....
}

For reasons only known to Microsoft, window.external.notify is undefined even though you can make calls to it without any issues.