Finding the longest branch in a binary image

2019-09-05 02:46发布

问题:

I am trying to find the longest branch in a skeleton image and show the final image as an output but stuck into the algorithm. Right now I am able to find a line and draw it in the output. but I need to find the longest line. This is what I've done so far:

    var vect1= new scala.collection.mutable.ArrayBuffer[Point]()
    var p=new Point (0,0)
    var res = new Array[Byte](1)
    var u=skel.get(p.x.toInt,p.y.toInt,res)
    var value1: Int=0
    var value2: Int=0
    scala.util.control.Breaks.breakable {
            while((value1 < skel.rows ) ){
                    while ( (value2 < skel.cols )){
                             if (res(0) == -1) {
                                    p.x=(p.x.toInt)+value1
                                    p.y=(p.y.toInt)+value2
                                    scala.util.control.Breaks.break()
                              }
                    value2=value2+1
                    skel.get(value1,value2,res)
                    }
            value2=0
            value1=value1+1
            }
    }

    vect1 = traceLine(skel, p);
     //inside traceLine the algorithm makes a vector and looks for 8 neighbors around the point to find the next available point and make the vector then return the result and save it into vect1.

val output= new Mat (skel.rows, skel.cols, CvType.CV_8UC3,new Scalar(0, 0, 0))
val it = vect1.iterator //Iterator(vect1)
var vect3=new Array[Byte](3)
vect3(0)=0
vect3(1)=255.toByte
vect3(2)=0
vect1.foreach(p => output.put(p.x.toInt, p.y.toInt, vect3))

Question is how can I return the longest branch?