Antlr4 grammar ambiguity

问题:

I have the following grammar ( minimized for SO)

grammar Hello;

odataIdentifier  : identifierLeadingCharacter identifierCharacter*; 


identifierLeadingCharacter : Alpha| UNDERSCORE;
identifierCharacter :  identifierLeadingCharacter | Digit;
identifierUnreserved    : identifierCharacter | (MINUS | DOT | TILDE);

Digit  : ZERO_TO_FIVE |[6-9];

ONEHUNDRED_TO_ONEHUNDREDNINETYNINE : '1' Digit Digit;            // 100-199
TWOHUNDRED_TO_TWOHUNDREDFOURTYNINE : '2' ZERO_TO_FOUR Digit;     // 200-249
TWOHUNDREDFIFTY_TO_TWOHUNDREDFIFTYFIVE : '25' ZERO_TO_FIVE;      // 250-255
TEN_TO_NINETYNINE : ONE_TO_NINE Digit;                           // 10-99

ZERO_TO_ONE : [0-1];
ZERO_TO_TWO : ZERO_TO_ONE | [2];
ZERO_TO_THREE : ZERO_TO_TWO | [3];
ZERO_TO_FOUR : ZERO_TO_THREE | [4];
ZERO_TO_FIVE : ZERO_TO_FOUR | [5];

ONE_TO_TWO  : [1-2];
ONE_TO_THREE  : ONE_TO_TWO | [3];
ONE_TO_FOUR  : ONE_TO_THREE | [4]; 
ONE_TO_NINE  : ONE_TO_FOUR | [5-9]; 

Alpha  : [a-zA-Z];

MINUS : [-];
DOT : '.';
UNDERSCORE : '_';
TILDE : '~';

WS  :  (' '|'\r'|'\t'|'\u000C'|'\n') -> skip
    ;

for input c9 it works fine, but when i have 2 digits for example c10 it says:

extraneous input '92' expecting {<EOF>, Digit, Alpha, '_'}

so i guess it parses 9 and parses 2 and doesn't know if this should be TEN_TO_NINETYNINE or 2 Digit Digit. i am a noob to this, so wondering if my analysis is right and how could i alleviate this ...

回答1:

Your input is resulting in an Alpha token followed by a TEN_TO_NINETYNINE token. While the parser rule identifierLeadingCharacter does allow the Alpha token, the identifierCharacter rule cannot match a TEN_TO_NINETYNINE token.

The input 10 will always produce a TEN_TO_NINETYNINE token rather than two Digit tokens, because the former matches more of the input and lexer rules are greedy.