我需要以书面形式在Oracle中查询以下数据帮助。 该数据是由人与天域排序。
Person Day Flag
------ --- ----
person1 day1 Y
person1 day2 Y
person1 day3 Y
person1 day4 N
person1 day5 N
person1 day6 Y
person1 day7 Y
person1 day8 Y
我需要有被递增每当标志值变化的GROUP_NUMBER列。 我的结果应该如下
Person Day Flag Group_Number
------ --- ---- ------------
person1 day1 Y 1
person1 day2 Y 1
person1 day3 Y 1
person1 day4 N 2
person1 day5 N 2
person1 day6 Y 3
person1 day7 Y 3
person1 day8 Y 3
我认为有办法使用分析功能，如ROW_NUMBER得到上述结果，铅等
你可以结合分析函数 SUM （用作运行总）和LAG ：
SQL> WITH data AS (
2 SELECT 'person1' person, 'day1' day, 'Y' flag FROM dual
3 UNION ALL SELECT 'person1' person, 'day2' day, 'Y' flag FROM dual
4 UNION ALL SELECT 'person1' person, 'day3' day, 'Y' flag FROM dual
5 UNION ALL SELECT 'person1' person, 'day4' day, 'N' flag FROM dual
6 UNION ALL SELECT 'person1' person, 'day5' day, 'N' flag FROM dual
7 UNION ALL SELECT 'person1' person, 'day6' day, 'Y' flag FROM dual
8 UNION ALL SELECT 'person1' person, 'day7' day, 'Y' flag FROM dual
9 UNION ALL SELECT 'person1' person, 'day8' day, 'Y' flag FROM dual
10 )
11 SELECT person, DAY, flag, SUM(gap) over (PARTITION BY person
12 ORDER BY DAY) grp
13 FROM (SELECT person, DAY, flag,
14 CASE WHEN flag = lag(flag) over (PARTITION BY person
15 ORDER BY DAY)
16 THEN 0
17 ELSE 1
18 END gap
19 FROM DATA);
PERSON DAY FLAG GRP
------- ---- ---- ----------
person1 day1 Y 1
person1 day2 Y 1
person1 day3 Y 1
person1 day4 N 2
person1 day5 N 2
person1 day6 Y 3
person1 day7 Y 3
person1 day8 Y 3
