我尝试以下代码转换的NSData为十六进制的字符串值,但都是错的?
这里的“结果”是我的NSData
我需要一个十六进制的字符串作为输出,但IAM没有得到这
NSUInteger dataLength = [result length];
NSLog(@"%d",dataLength);
NSMutableString *string = [NSMutableString stringWithCapacity:dataLength*2];
const unsigned char *dataBytes = [result bytes];
for (NSInteger idx = 0; idx < dataLength; ++idx) { [string appendFormat:@"%02x", dataBytes[idx]];
}
NSLog(@"%@",string);
我怎么能转换这个请
更新:结果数据中包含加密的字符串。我想将其转换为十六进制值
这是一类,我有这样做的。 这只是给你在十六进制数据的所有字符。 没有换行符或任何东西。
@implementation NSData (NSData_Conversion)
#pragma mark - String Conversion
- (NSString *)hexadecimalString
{
/* Returns hexadecimal string of NSData. Empty string if data is empty. */
const unsigned char *dataBuffer = (const unsigned char *)[self bytes];
if (!dataBuffer)
{
return [NSString string];
}
NSUInteger dataLength = [self length];
NSMutableString *hexString = [NSMutableString stringWithCapacity:(dataLength * 2)];
for (int i = 0; i < dataLength; ++i)
{
[hexString appendFormat:@"%02x", (unsigned int)dataBuffer[i]];
}
return [NSString stringWithString:hexString];
}
最简单的解决办法是循环通NSData的的字节,并从它构造的NSString。 使用[yourData字节]进入字节,并建立串入的NSMutableString。
以下是通过实施本NSData的使用的一类的例子
interface NSData(Hex)
-(NSString*)hexRepresentationWithSpaces_AS:(BOOL)spaces;
@end
@implementation NSData(Hex)
-(NSString*)hexRepresentationWithSpaces_AS:(BOOL)spaces
{
const unsigned char* bytes = (const unsigned char*)[self bytes];
NSUInteger nbBytes = [self length];
//If spaces is true, insert a space every this many input bytes (twice this many output characters).
static const NSUInteger spaceEveryThisManyBytes = 4UL;
//If spaces is true, insert a line-break instead of a space every this many spaces.
static const NSUInteger lineBreakEveryThisManySpaces = 4UL;
const NSUInteger lineBreakEveryThisManyBytes = spaceEveryThisManyBytes * lineBreakEveryThisManySpaces;
NSUInteger strLen = 2*nbBytes + (spaces ? nbBytes/spaceEveryThisManyBytes : 0);
NSMutableString* hex = [[NSMutableString alloc] initWithCapacity:strLen];
for(NSUInteger i=0; i<nbBytes; ) {
[hex appendFormat:@"%02X", bytes[i]];
//We need to increment here so that the every-n-bytes computations are right.
++i;
if (spaces) {
if (i % lineBreakEveryThisManyBytes == 0) [hex appendString:@"\n"];
else if (i % spaceEveryThisManyBytes == 0) [hex appendString:@" "];
}
}
return [hex autorelease];
}
@end
NSData* data = ...
NSString* hex = [data hexRepresentationWithSpaces_AS:YES];
这是整数运算转换:
-(NSString*)hex:(NSData*)data{
NSMutableData *result = [NSMutableData dataWithLength:2*data.length];
unsigned const char* src = data.bytes;
unsigned char* dst = result.mutableBytes;
unsigned char t0, t1;
for (int i = 0; i < data.length; i ++ ) {
t0 = src[i] >> 4;
t1 = src[i] & 0x0F;
dst[i*2] = 48 + t0 + (t0 / 10) * 39;
dst[i*2+1] = 48 + t1 + (t1 / 10) * 39;
}
return [[NSString alloc] initWithData:result encoding:NSASCIIStringEncoding];
}
斯威夫特2版
private let kHexChars = Array("0123456789abcdef".utf8) as [UInt8];
extension NSData {
public func hexString() -> String {
guard length > 0 else {
return ""
}
let buffer = UnsafeBufferPointer<UInt8>(start: UnsafePointer(bytes), count: length)
var output = [UInt8](count: length*2 + 1, repeatedValue: 0)
var i: Int = 0
for b in buffer {
let h = Int((b & 0xf0) >> 4)
let l = Int(b & 0x0f)
output[i++] = kHexChars[h]
output[i++] = kHexChars[l]
}
return String.fromCString(UnsafePointer(output))!
}
}
这个答案是在雨燕4.2运行在一个Xcode 10游乐场。
import Foundation
let d = Data(bytes: [0x3f, 0x09, 0x0a, 0xa3, 0x01])
let s:String = d.compactMap({ String(format: "%02x ", $0) }).joined()
print(s)
下面是输出:
3f 09 0a a3 01