如何实现Parcelable一个包含类列表 (How to implement Parcelabl

2019-09-02 14:24发布

I have a working Parcelable implementaion for all the fields in my Parcelable Class apart from List<List<String>>

class Employee implements Parcelable {

    List<List<String>> details;
    //.......

    protected Employee(Parcel in) {
        details = new ArrayList<List<String>>();
        // i know this is wrong just posting to clarify
        in.readList(details, List.class.getClassLoader());
        //......
    }

    public void writeToParcel(Parcel dest, int flags) {
        dest.writeList(details);
        //.....
    }

    public int describeContents() {
        return 0;
    }

    public static final Parcelable.Creator<Employee> CREATOR = 
            new Parcelable.Creator<Employee>() {
        public Employee createFromParcel(Parcel in) {
            return new Employee(in);
        }

        public Employee[] newArray(int size) {
            return new Employee[size];
        }
    };

}

Exception:

05-10 19:07:44.072: E/AndroidRuntime(10661): Caused by: java.lang.RuntimeException: Parcel android.os.Parcel@42a509e8: Unmarshalling unknown type code 3604535 at offset 268

Answer 1:

扩展ArrayList和实现Parcelable它为我工作。

public class ParcelableArrayList extends ArrayList<String> implements 
        Parcelable {

    private static final long serialVersionUID = -8516873361351845306L;

    public ParcelableArrayList(){
        super();
    }

    protected ParcelableArrayList(Parcel in) {
        in.readList(this, String.class.getClassLoader());
    }

    @Override
    public int describeContents() {
        return 0;
    }

    @Override
    public void writeToParcel(Parcel dest, int flags) {
        dest.writeList(this);
    }   

    public static final Parcelable.Creator<ParcelableArrayList> CREATOR = 
            new Parcelable.Creator<ParcelableArrayList>() {
        public ParcelableArrayList createFromParcel(Parcel in) {
            return new ParcelableArrayList(in);
        }

        public ParcelableArrayList[] newArray(int size) {
            return new ParcelableArrayList[size];
        }
    };

}

和Employee类

class Employee implements Parcelable {

    List<ParcelableArrayList> details;
    //.......

    protected Employee(Parcel in) {
        details = new ArrayList<ParcelableArrayList>();
        in.readTypedList(details,ParcelableArrayList.CREATOR);
        //......
    }

    public void writeToParcel(Parcel dest, int flags) {
        dest.writeList(details);
        //.....
    }

    public int describeContents() {
        return 0;
    }

    public static final Parcelable.Creator<Employee> CREATOR = 
            new Parcelable.Creator<Employee>() {
        public Employee createFromParcel(Parcel in) {
            return new Employee(in);
        }

        public Employee[] newArray(int size) {
            return new Employee[size];
        }
    };

}


Answer 2:

我想创建一个扩展列表中的一个类,这个类的实现Parcelable。 另外您也可以把它当作一个正常的列表,但允许它是parcelable。



Answer 3:

创建class DetailsEntry implements Parcelable其中包含List<String>和使用List<DetailsEntry> detailsEmployee



文章来源: How to implement Parcelable for a class containing List>?