I need to serialize/deserialize a Scala class with structure something like the following:
@JsonIgnoreProperties(ignoreUnknown = true, value = Array("body"))
case class Example(body: Array[Byte]) {
lazy val isNativeText = bodyIsNativeText
lazy val textEncodedBody = (if (isNativeText) new String(body, "UTF-8") else Base64.encode(body))
def this(isNativeText: Boolean, textEncodedBody: String) = this((if(isNativeText) str.getBytes("UTF-8") else Base64.decode(textEncodedBody)))
def bodyIsNativeText: Boolean = // determine if the body was natively a string or not
}
It's main member is an array of bytes, which MIGHT represent a UTF-8 encoded textual string, but might not. The primary constructor accepts an array of bytes, but there is an alternate constructor which accepts a string with a flag indicating whether this string is base64 encoded binary data, or the actual native text we want to store.
For serializing to a JSON object, I want to store the body as a native string rather than a base64-encoded string if it is native text. That's why I use @JsonIgnoreProperties
to not include the body
property, and instead have a textEncodedBody
that gets echoed out in the JSON.
The problem comes when I try to deserialize it like so:
val e = Json.parse[Example]("""{'isNativeText': true, 'textEncodedBody': 'hello'}""")
I receive the following error:
com.codahale.jerkson.ParsingException: Invalid JSON. Needed [body], but found [isNativeText, textEncodedBody].
Clearly, I have a constructor that will work...it just is not the default one. How can I force Jerkson to use this non-default constructor?
EDIT: I've attempted to use both the @JsonProperty
and @JsonCreator
annotation, but jerkson appears to disregard both of those.
EDIT2: Looking over the jerkson case class serialization source code, it looks like a case class method with the same name as its field will be used in the way that a @JsonProperty
would function - that is, as a JSON getter. If I could do that, it would solve my problem. Not being super familiar with Scala, I have no idea how to do that; is it possible for a case class to have a user-defined method with the same name as one of its fields?
For reference, here is the code below that leads me to this conclusion...
private val methods = klass.getDeclaredMethods
.filter { _.getParameterTypes.isEmpty }
.map { m => m.getName -> m }.toMap
def serialize(value: A, json: JsonGenerator, provider: SerializerProvider) {
json.writeStartObject()
for (field <- nonIgnoredFields) {
val methodOpt = methods.get(field.getName)
val fieldValue: Object = methodOpt.map { _.invoke(value) }.getOrElse(field.get(value))
if (fieldValue != None) {
val fieldName = methodOpt.map { _.getName }.getOrElse(field.getName)
provider.defaultSerializeField(if (isSnakeCase) snakeCase(fieldName) else fieldName, fieldValue, json)
}
}
json.writeEndObject()
}