这里有一个简单的语法测试,我以为会很容易解析,但我得到“不匹配输入”马上蝙蝠,我想不出什么ANTLR的所期待的。
输入:
# include "something" program TEST1 { BLAH BLAH }
我的语法:
grammar ProgHeader;
program: header* prog EOF ;
header: '#' ( include | define ) ;
include: 'include' string ;
define: 'define' string string? ;
string: '"' QTEXT '"' ;
prog: 'program' QTEXT '{' BLOCK '}' ;
QTEXT: ~[\r\n\"]+ ;
BLOCK: ~[}]+ ; // don't care, example block
WS: [ \t\r\n] -> skip ;
输出错误消息:
line 1:0 mismatched input '# include "something" program TEST1 { BLAH BLAH '
expecting {'program', '#'}
这确实让我困惑,因为它说,它在寻找一个“#”,并有在输入的开始一个权利。 我甩解析树了。 这似乎是在右上角卡,在“程序”规则:
(program # include "something" program TEST1 { BLAH BLAH } )
HALP?
下面是完整的程序推动这一测试情况下,如果它的事项(我不认为它应该的问题,上面的信息就足够了,但在这里它是):
package antlrtests;
import antlrtests.grammars.*;
import org.antlr.v4.runtime.*;
import org.antlr.v4.runtime.tree.*;
/**
*
* @author Brenden Towey
*/
public class ProgHeaderTest {
private String[] testVectors = {
"# include \"something\" program TEST1 { BLAH BLAH } ",
};
public void runTests() {
for( String test : testVectors )
simpleTest( test );
}
private void simpleTest( String test ) {
ANTLRInputStream ains = new ANTLRInputStream( test );
ProgHeaderLexer wpl = new ProgHeaderLexer( ains );
CommonTokenStream tokens = new CommonTokenStream( wpl );
ProgHeaderParser wikiParser = new ProgHeaderParser( tokens );
ParseTree parseTree = wikiParser.program();
System.out.println( "'" + test + "': " + parseTree.toStringTree(
wikiParser ) );
}
}
而完整的输出:
run:
line 1:0 mismatched input '# include "something" program TEST1 { BLAH BLAH ' expecting {'program', '#'}
'# include "something" program TEST1 { BLAH BLAH } ': (program # include "something" program TEST1 { BLAH BLAH } )
BUILD SUCCESSFUL (total time: 0 seconds)