I'm trying to remove the last segment of a given URI using Ruby,
like this:
http://example.com/foo/bar/baz/?lala=foo
How can I get this :
"http://example.com/foo/bar/baz/"
I've searched and all that I got is to get the last segment or the host part of the URI.
Based on your comment to @JorgWMittag all your really need is this
s = 'http://example.com/foo/bar/baz/?lala=foo#quux'
s[/.*\//]
#=> "http://example.com/foo/bar/baz/"
s = 'http://example.com/foo/bar.html'
s[/.*\//]
#=> "http://example.com/foo/"
Basically it just says grab the substring up to the last slash obviously if you have things like
s = "http://example.com/foo/bar/?baz=/blah/blah"
Then this will not work but your question and specifications seem very loose at the moment.
The most important thing to remember is: Ruby is an object-oriented language. It's not an array-oriented language, it's not a hash-oriented language, it's not a string-oriented language.
When you want to do something, you construct an object which represents your concept and manipulate that object. In this case, you want to manipulate a URI, so you need to construct an object which represents a URI.
Thankfully, the Ruby standard library already contains a ready-made class for such objects:
require 'uri'
uri = URI.parse('http://example.com/foo/bar/baz/?lala=foo#quux')
uri.query = nil
uri
# => #<URI::HTTP http://example.com/foo/bar/baz/#quux>
uri.to_s
# => 'http://example.com/foo/bar/baz/#quux'
uri.fragment = nil
uri
# => #<URI::HTTP http://example.com/foo/bar/baz/>
uri.to_s
# => 'http://example.com/foo/bar/baz/'
As you can see, once you create a proper object representing your URI, manipulating it becomes trivial.
s = "http://example.com/foo/bar/baz/?lala=foo"
"http://example.com/foo/bar/baz/?lala=foo"
["http://example.com/foo/bar/baz/", "lala=foo"]
>> s.split("?").first
"http://example.com/foo/bar/baz/"
Did you tried something like this, possibly the first thing when you want to split a string
