嗨“我要申请编号的混合物和蛞蝓的网址在我的博客网址是这样
http://stackoverflow.com/questions/16286556/using-httpclient-to-log-in-to-hpps-server
要做到这一点我在Global.asax中定义以下链接
routes.MapRoute("IdSlugRoute", "{controller}/{action}/{id}/{slug}",
new {controller = "Blog", action = "Post", id = UrlParameter.Optional,slug=""});
但是当我运行我的应用程序URL是这个样子:
http://localhost:1245/Blog/Post?postId=dd1140ce-ae5e-4003-8090-8d9fbe253e85&slug=finally-i-could-do-solve-it
我不希望有那些? 和=以网址! 我只是想通过斜线我该怎么办这个,请把它们分开?
卜的方式,返回此URL的ActionResult是这样的:
public ActionResult Post(Guid postId,string slug)
{
var post = _blogRepository.GetPostById(postId);
return View("Post",post);
}
您是否尝试过设置你都和帖子ID蛞蝓是UrlParameter.Optional
? routes.MapRoute("IdSlugRoute", "{controller}/{action}/{postId}/{slug}", new {controller = "Blog", action = "Post", postId = UrlParameter.Optional,slug=UrlParameter.Optional});
编辑
我得到这个在当地工作。 我所得到的是一个模式:
public class HomeViewModel
{
public Guid PostID { get; set; }
public string Slug { get; set; }
}
有两个动作控制器:
public class HomeController : Controller
{
public ActionResult Index()
{
Guid guid = Guid.NewGuid();
var model = new HomeViewModel { PostID = guid, Slug = "this-is-a-test" };
return View(model);
}
public ActionResult Post(Guid postID, string slug)
{
// get the post based on postID
}
}
并与ActionLink的一个观点:
@model MvcApplication1.Models.HomeViewModel
@{
ViewBag.Title = "Home Page";
}
@Html.ActionLink("Click me!", "Post", new { postId = Model.PostID, slug = Model.Slug})
为了让路由的工作,我不得不硬编码的路线,因为它涉及的默认路由之前:
public static void RegisterRoutes(RouteCollection routes)
{
routes.IgnoreRoute("{resource}.axd/{*pathInfo}");
routes.MapRoute("IdSlugRoute", "Home/Post/{postID}/{slug}",
new { controller = "Home", action = "Post", postID = Guid.Empty, slug = UrlParameter.Optional });
routes.MapRoute(
"Default", // Route name
"{controller}/{action}/{id}", // URL with parameters
new { controller = "Home", action = "Index", id = UrlParameter.Optional } // Parameter defaults
);
}
确保您的自定义路由高于默认的。 它会停在它找到的第一个匹配的路由。
改变你的路线,用帖子ID,而不是标识
routes.MapRoute("IdSlugRoute", "{controller}/{action}/{postId}/{slug}",
new {controller = "Blog", action = "Post", postId = UrlParameter.Optional,slug=""});