当我试图执行SQL Server中下面的代码,2005年,我正在错误
无效的列名DistanceFromAddress
码:
select
SQRT(POWER(cast(Program_Latitude as float) - cast('41.5126237' as float), 2) +
POWER(cast(Program_Longitude as float) - cast('-81.6516411' as float), 2)) * 62.1371192 AS DistanceFromAddress
from
tblProgram
where
DistanceFromAddress < 2
我得到的值正确使用SELECT语句,但是当我试图检查的条件where DistanceFromAddress < 2
我得到的错误。
我怎样才能解决这个问题呢?
你不能在使用别名列WHERE
子句。 您可以尝试使用派生表。 也许这样的事情(对不起,未测试):
SELECT * FROM
(SELECT SQRT(POWER(cast(Program_Latitude as float) - cast('41.5126237' as float), 2) +
POWER(cast(Program_Longitude as float) - cast('-81.6516411' as float), 2)) * 62.1371192
AS DistanceFromAddress from tblProgram) mytable
WHERE DistanceFromAddress < 2
的WHERE
子句的前处理SELECT
从句(*),因此别名不可用。 移动到使用子查询或CTE -这里有一个CTE:
; with Distances as (
select SQRT(POWER(cast(Program_Latitude as float) - cast('41.5126237' as float), 2) +
POWER(cast(Program_Longitude as float) - cast('-81.6516411' as float), 2)) * 62.1371192
AS DistanceFromAddress
from tblProgram
)
select * from Distances where DistanceFromAddress < 2
(*) -阱,系统是免费的,因为他们认为合适的重新排序操作,只要结果是“好像” SQL语句是在一定的处理逻辑顺序 。 当然,在这一切都错了与SQL Server是它产生错误因为在转换问题SELECT
的行/值条款,应当由被淘汰WHERE
子句。
select
SQRT(
POWER(cast(Program_Latitude as float) - cast('41.5126237' as float), 2) +
POWER(cast(Program_Longitude as float) - cast('-81.6516411' as float), 2)
) * 62.1371192 AS DistanceFromAddress
from tblProgram
having DistanceFromAddress < 2
可以工作(虽然我认为不会,而无需GROUP BY子句为好)。
问题是,你只能使用名称表中(S)的范围,你里面选择where
的条款。 Where
是预过滤器,过滤出选择行之前他们,所以像这样的表达式中的字段定义尚未执行,并且别名为此不可用。
在Having
条款可以作为一个后置滤波器分组后,可以使用别名从查询,但我怕你将需要有一个实际的group by
子句(不知道)。
另一种方法是为具有子选择(派生的表或在所选择的选择),其中,首先选择每一行的距离,然后选择只能从这些结果的相关距离。 这将工作:
select d.DistanceFromAddress
from
(select
SQRT(
POWER(cast(Program_Latitude as float) - cast('41.5126237' as float), 2) +
POWER(cast(Program_Longitude as float) - cast('-81.6516411' as float), 2)
) * 62.1371192 AS DistanceFromAddress
from tblProgram) d
where d.DistanceFromAddress < 2
或者你可以重复表达。 这使得您的查询更难维护,但在某些情况下,这可能会为你工作。 例如,如果你不会想返回的实际距离,但只,说,利益在这个距离点的名称。 在这种情况下,你需要有唯一的表达where
条款,在这种情况下,维护说法走了,这解决方案是一个完美的选择。
select
tblProgram.POIname
/* Only if you need to return the actual value
, SQRT(
POWER(cast(Program_Latitude as float) - cast('41.5126237' as float), 2) +
POWER(cast(Program_Longitude as float) - cast('-81.6516411' as float), 2)
) * 62.1371192 AS DistanceFromAddress */
from tblProgram
where
-- Use this if you only want to filter by the value.
SQRT(
POWER(cast(Program_Latitude as float) - cast('41.5126237' as float), 2) +
POWER(cast(Program_Longitude as float) - cast('-81.6516411' as float), 2)
) * 62.1371192 < 2
我想你只能用作显示最终值。 为了做一个比较,选择应当从里面另一个选择语句返回。
喜欢:
SELECT a.disfromaddr FROM
( SELECT SQRT(POWER(cast(Program_Latitude as float) - cast('41.5126237' as float), 2) +
POWER(cast(Program_Longitude as float) - cast('-81.6516411' as float), 2)) * 62.1371192
AS DistanceFromAddress FROM tblProgram)
a WHERE a.disfromaddr < 2
你可以试试这个。