试图运行AWK可执行文件时，“坏的解释”错误信息(“bad interpreter” error m

我试图做一个awk文件可执行。我写剧本，并没有chmod +x filename 。下面是代码：

#!/bin/awk -v

'TOPNUM = $1

## pick1 - pick one random number out of y
## main routine

BEGIN {
## set seed
        srand ()

## get a random number

        select = 1 +int(rand() * TOPNUM)

# print pick
        print select
}'

当我尝试和运行计划，并为一个变量TOPNUM ：

pick1 50

我得到的回应：

-bash: /home/petersone/bin/pick1: /bin/awk: bad interpreter: No such file or directory

我敢肯定，有一些简单的我搞乱了，但我根本无法弄清楚它是什么。我怎样才能解决这个问题？

Answer 1:

From a command line, run this command:

which awk

This will print the path of AWK, which is likely /usr/bin/awk. Correct the first line and your script should work.

Also, your script shouldn't have the single-quote characters at the beginning and end. You can run AWK from the command line and pass in a script as a quoted string, or you can write a script in a file and use the #!/usr/bin/awk first line, with the commands just in the file.

Also, the first line of your script isn't going to work right. In AWK, setup code needs to be inside the BEGIN block, and $1 is a reference to the first word in the input line. You need to use ARGV[1] to refer to the first argument.

http://www.gnu.org/software/gawk/manual/html_node/ARGC-and-ARGV.html

As @TrueY pointed out, there should be a -f on the first line:

#!/usr/bin/awk -f

This is discussed here: Invoking a script, which has an awk shebang, with parameters (vars)

Working, tested version of the program:

#!/usr/bin/awk -f

## pick1 - pick one random number out of y
## main routine
BEGIN {
    TOPNUM = ARGV[1]

## set seed
        srand ()

## get a random number

        select = 1 +int(rand() * TOPNUM)

# print pick
        print select
}