如何加快python的“海龟”的功能,并停止其在最后冻结(How to speed up pytho

2019-08-31 14:48发布

我已经用Python编写的乌龟程序,但有两个问题。

  1. 这也适用于更大的数字方式太慢了,我不知道如何可以加快乌龟。
  2. 它冻结它完成和点击时,表示“没有响应”后

这是我到目前为止的代码:

import turtle

#Takes user input to decide how many squares are needed
f=int(input("How many squares do you want?"))
c=int(input("What colour would you like? red = 1, blue = 2 and green =3"))
n=int(input("What background colour would you like? red = 1, blue = 2 and green =3"))

i=1

x=65

#Draws the desired number of squares.
while i < f:
    i=i+1
    x=x*1.05
    print ("minimise this window ASAP")
    if c==1:
        turtle.pencolor("red")
    elif c==2:
        turtle.pencolor("blue")
    elif c==3:
        turtle.pencolor("green")
    else:
        turtle.pencolor("black")
    if n==1:
        turtle.fillcolor("red")
    elif n==2:
        turtle.fillcolor("blue")
    elif n==3:
        turtle.fillcolor("green")
    else:
        turtle.fillcolor("white")
    turtle.bk(x)
    turtle.rt(90)
    turtle.bk(x)
    turtle.rt(90)
    turtle.bk(x)
    turtle.rt(90)
    turtle.bk(x)
    turtle.rt(90)
    turtle.up()
    turtle.rt(9)
    turtle.down()

顺便说一句:我在3.2版本!

Answer 1:

  1. 设置turtle.speed()fastest
  2. 使用turtle.mainloop()功能做的工作,而屏幕刷新。
  3. 禁用屏幕刷新turtle.tracer(0, 0)然后在最后做turtle.update()


Answer 2:

Python的乌龟去得非常缓慢,因为每次修改到龟作出后进行屏幕刷新。

您可以禁用刷新画面,直到所有的工作完成后,然后画在屏幕上,它会消除毫秒延迟作为屏幕拼命试图从每一个龟变化更新屏幕。

例如:

import turtle
import random
import time
screen = turtle.Screen()

turtlepower = []

turtle.tracer(0, 0)
for i in range(1000):
    t = turtle.Turtle()
    t.goto(random.random()*500, random.random()*1000)
    turtlepower.append(t)

for i in range(1000):
    turtle.stamp()

turtle.update()

time.sleep(3)

此代码千年龟在随机位置,并显示在大约200毫秒的图片。

如果你不是禁用屏幕刷新turtle.tracer(0, 0)命令,它会因为它试图刷新屏幕3000次采取了几分钟。

https://docs.python.org/2/library/turtle.html#turtle.delay



Answer 3:

作为参考,龟正在缓慢是现有的问题。 即使速度设置为最大值,乌龟可以采取类似的东西分形相当长的时间。 尼克·奥德尔重新实现速度龟在这里: 隐藏龟窗口?

import math

class UndrawnTurtle():
def __init__(self):
    self.x, self.y, self.angle = 0.0, 0.0, 0.0
    self.pointsVisited = []
    self._visit()

def position(self):
    return self.x, self.y

def xcor(self):
    return self.x

def ycor(self):
    return self.y

def forward(self, distance):
    angle_radians = math.radians(self.angle)

    self.x += math.cos(angle_radians) * distance
    self.y += math.sin(angle_radians) * distance

    self._visit()

def backward(self, distance):
    self.forward(-distance)

def right(self, angle):
    self.angle -= angle

def left(self, angle):
    self.angle += angle

def setpos(self, x, y = None):
    """Can be passed either a tuple or two numbers."""
    if y == None:
        self.x = x[0]
        self.y = x[1]
    else:
        self.x = x
        self.y = y
    self._visit()

def _visit(self):
    """Add point to the list of points gone to by the turtle."""
    self.pointsVisited.append(self.position())

# Now for some aliases. Everything that's implemented in this class
# should be aliased the same way as the actual api.
fd = forward
bk = backward
back = backward
rt = right
lt = left
setposition = setpos
goto = setpos
pos = position

ut = UndrawnTurtle()


文章来源: How to speed up python's 'turtle' function and stop it freezing at the end