HashMap with multiple values under the same key

问题:

Is it possible for us to implement a HashMap with one key and two values. Just as HashMap?

Please do help me, also by telling (if there is no way) any other way to implement the storage of three values with one as the key?

回答1:

You could:

1. Use a map that has a list as the value. Map<KeyType, List<ValueType>>.
2. Create a new wrapper class and place instances of this wrapper in the map. Map<KeyType, WrapperType>.
3. Use a tuple like class (saves creating lots of wrappers). Map<KeyType, Tuple<Value1Type, Value2Type>>.
4. Use mulitple maps side-by-side.

---

Examples

1. Map with list as the value

// create our map
Map<String, List<Person>> peopleByForename = new HashMap<>();    

// populate it
List<Person> people = new ArrayList<>();
people.add(new Person(\"Bob Smith\"));
people.add(new Person(\"Bob Jones\"));
peopleByForename.put(\"Bob\", people);

// read from it
List<Person> bobs = peopleByForename[\"Bob\"];
Person bob1 = bobs[0];
Person bob2 = bobs[1];

The disadvantage with this approach is that the list is not bound to exactly two values.

2. Using wrapper class

// define our wrapper
class Wrapper {
    public Wrapper(Person person1, Person person2) {
       this.person1 = person1;
       this.person2 = person2;
    }

    public Person getPerson1 { return this.person1; }
    public Person getPerson2 { return this.person2; }

    private Person person1;
    private Person person2;
}

// create our map
Map<String, Wrapper> peopleByForename = new HashMap<>();

// populate it
Wrapper people = new Wrapper()
peopleByForename.put(\"Bob\", new Wrapper(new Person(\"Bob Smith\"),
                                        new Person(\"Bob Jones\"));

// read from it
Wrapper bobs = peopleByForename[\"Bob\"];
Person bob1 = bobs.Person1;
Person bob2 = bobs.Person2;

The disadvantage to this approach is that you have to write a lot of boiler-plate code for all of these very simple container classes.

3. Using a tuple

// you\'ll have to write or download a Tuple class in Java, (.NET ships with one)

// create our map
Map<String, Tuple2<Person, Person> peopleByForename = new HashMap<>();

// populate it
peopleByForename.put(\"Bob\", new Tuple2(new Person(\"Bob Smith\",
                                       new Person(\"Bob Jones\"));

// read from it
Tuple<Person, Person> bobs = peopleByForename[\"Bob\"];
Person bob1 = bobs.Item1;
Person bob2 = bobs.Item2;

This is the best solution in my opinion.

4. Multiple maps

// create our maps
Map<String, Person> firstPersonByForename = new HashMap<>();
Map<String, Person> secondPersonByForename = new HashMap<>();

// populate them
firstPersonByForename.put(\"Bob\", new Person(\"Bob Smith\"));
secondPersonByForename.put(\"Bob\", new Person(\"Bob Jones\"));

// read from them
Person bob1 = firstPersonByForename[\"Bob\"];
Person bob2 = secondPersonByForename[\"Bob\"];

The disadvantage of this solution is that it\'s not obvious that the two maps are related, a programmatic error could see the two maps get out of sync.

回答2:

No, not just as a HashMap. You\'d basically need a HashMap from a key to a collection of values.

If you\'re happy to use external libraries, Guava has exactly this concept in Multimap with implementations such as ArrayListMultimap and HashMultimap.

回答3:

Another nice choice is to use MultiValuedMap from Apache Commons. Take a look at the All Known Implementing Classes at the top of the page for specialized implementations.

Example:

HashMap<K, ArrayList<String>> map = new HashMap<K, ArrayList<String>>()

could be replaced with

MultiValuedMap<K, String> map = new MultiValuedHashMap<K, String>();

So,

map.put(key, \"A\");
map.put(key, \"B\");
map.put(key, \"C\");

Collection<String> coll = map.get(key);

would result in collection coll containing \"A\", \"B\", and \"C\".

回答4:

Take a look at Multimap from the guava-libraries and its implementation - HashMultimap

A collection similar to a Map, but which may associate multiple values with a single key. If you call put(K, V) twice, with the same key but different values, the multimap contains mappings from the key to both values.

回答5:

I use Map<KeyType, Object[]> for associating multiple values with a key in a Map. This way, I can store multiple values of different types associated with a key. You have to take care by maintaining proper order of inserting and retrieving from Object[].

Example: Consider, we want to store Student information. Key is id, while we would like to store name, address and email associated to the student.

       //To make entry into Map
        Map<Integer, String[]> studenMap = new HashMap<Integer, String[]>();
        String[] studentInformationArray = new String[]{\"name\", \"address\", \"email\"};
        int studenId = 1;
        studenMap.put(studenId, studentInformationArray);

        //To retrieve values from Map
        String name = studenMap.get(studenId)[1];
        String address = studenMap.get(studenId)[2];
        String email = studenMap.get(studenId)[3];

回答6:

HashMap<Integer,ArrayList<String>> map = new    HashMap<Integer,ArrayList<String>>();

ArrayList<String> list = new ArrayList<String>();
list.add(\"abc\");
list.add(\"xyz\");
map.put(100,list);

回答7:

Just for the record, the pure JDK8 solution would be to use Map::compute method:

map.compute(key, (s, strings) -> strings == null ? new ArrayList<>() : strings).add(value);

Such as

public static void main(String[] args) {
    Map<String, List<String>> map = new HashMap<>();

    put(map, \"first\", \"hello\");
    put(map, \"first\", \"foo\");
    put(map, \"bar\", \"foo\");
    put(map, \"first\", \"hello\");

    map.forEach((s, strings) -> {
        System.out.print(s + \": \");
        System.out.println(strings.stream().collect(Collectors.joining(\", \")));
    });
}

private static <KEY, VALUE> void put(Map<KEY, List<VALUE>> map, KEY key, VALUE value) {
    map.compute(key, (s, strings) -> strings == null ? new ArrayList<>() : strings).add(value);
}

with output:

bar: foo
first: hello, foo, hello

Note that to ensure consistency in case multiple threads access this data structure, ConcurrentHashMap and CopyOnWriteArrayList for instance need to be used.

回答8:

If you use Spring Framework. There is: org.springframework.util.MultiValueMap.

To create unmodifiable multi value map:

Map<String,List<String>> map = ...
MultiValueMap<String, String> multiValueMap = CollectionUtils.toMultiValueMap(map);

Or use org.springframework.util.LinkedMultiValueMap

回答9:

Yes and no. The solution is to build a Wrapper clas for your values that contains the 2 (3, or more) values that correspond to your key.

回答10:

Yes, this is frequently called a multimap.

See: http://google-collections.googlecode.com/svn/trunk/javadoc/index.html?com/google/common/collect/Multimap.html

回答11:

The easiest way would be to use a google collection library:

import com.google.common.collect.ArrayListMultimap; import com.google.common.collect.Multimap;

public class Test {

public static void main(final String[] args) {

    // multimap can handle one key with a list of values
    final Multimap<String, String> cars = ArrayListMultimap.create();
    cars.put(\"Nissan\", \"Qashqai\");
    cars.put(\"Nissan\", \"Juke\");
    cars.put(\"Bmw\", \"M3\");
    cars.put(\"Bmw\", \"330E\");
    cars.put(\"Bmw\", \"X6\");
    cars.put(\"Bmw\", \"X5\");

    cars.get(\"Bmw\").forEach(System.out::println);

    // It will print the:
    // M3
    // 330E
    // X6
    // X5
}

}

maven link: https://mvnrepository.com/artifact/com.google.collections/google-collections/1.0-rc2

more on this: http://tomjefferys.blogspot.be/2011/09/multimaps-google-guava.html

回答12:

I could not post a reply on Paul\'s comment so I am creating new comment for Vidhya here:

Wrapper will be a SuperClass for the two classes which we want to store as a value.

and inside wrapper class, we can put the associations as the instance variable objects for the two class objects.

e.g.

class MyWrapper {

 Class1 class1obj = new Class1();
 Class2 class2obj = new Class2();
...
}

and in HashMap we can put in this way,

Map<KeyObject, WrapperObject> 

WrapperObj will have class variables: class1Obj, class2Obj

回答13:

You can do it implicitly.

// Create the map. There is no restriction to the size that the array String can have
HashMap<Integer, String[]> map = new HashMap<Integer, String[]>();

//initialize a key chosing the array of String you want for your values
map.put(1, new String[] { \"name1\", \"name2\" });

//edit value of a key
map.get(1)[0] = \"othername\";

This is very simple and effective. If you want values of diferent classes instead, you can do the following:

HashMap<Integer, Object[]> map = new HashMap<Integer, Object[]>();

回答14:

Can be done using an identityHashMap, subjected to the condition that the keys comparison will be done by == operator and not equals().

回答15:

I prefer the following to store any number of variables without having to create a separate class.

final public static Map<String, Map<String, Float>> myMap    = new HashMap<String, Map<String, Float>>();

回答16:

Here is THE ANSWER : ) : )

String key= \"services_servicename\"

ArrayList data;

for(int i = 0; i lessthen data.size(); i++){

        HashMap<String, String> servicesNameHashmap = new HashMap<String, String>();
        servicesNameHashmap.put(key,data.get(i).getServiceName());
        mServiceNameArray.add(i,servicesNameHashmap);   }

I have got the Best Results.

You Just Have to Create New HashMap Like

HashMap servicesNameHashmap = new HashMap();

in Your For Loop. It will have Same Effect Like Same Key And Multiple Values.

Happy Coding :)

回答17:

I am so used to just doing this with a Data Dictionary in Objective C. It was harder to get a similar result in Java for Android. I ended up creating a custom class, and then just doing a hashmap of my custom class.

public class Test1 {
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.addview);

//create the datastring
    HashMap<Integer, myClass> hm = new HashMap<Integer, myClass>();
    hm.put(1, new myClass(\"Car\", \"Small\", 3000));
    hm.put(2, new myClass(\"Truck\", \"Large\", 4000));
    hm.put(3, new myClass(\"Motorcycle\", \"Small\", 1000));

//pull the datastring back for a specific item.
//also can edit the data using the set methods.  this just shows getting it for display.
    myClass test1 = hm.get(1);
    String testitem = test1.getItem();
    int testprice = test1.getPrice();
    Log.i(\"Class Info Example\",testitem+Integer.toString(testprice));
}
}

//custom class.  You could make it public to use on several activities, or just include in the activity if using only here
class myClass{
    private String item;
    private String type;
    private int price;

    public myClass(String itm, String ty, int pr){
        this.item = itm;
        this.price = pr;
        this.type = ty;
    }

    public String getItem() {
        return item;
    }

    public void setItem(String item) {
        this.item = item;
    }

    public String getType() {
        return item;
    }

    public void setType(String type) {
        this.type = type;
    }

    public int getPrice() {
        return price;
    }

    public void setPrice(int price) {
        this.price = price;
    }

}

回答18:

We can create a class to have multiple keys or values and the object of this class can be used as a parameter in map. You can refer to https://stackoverflow.com/a/44181931/8065321

回答19:

Try LinkedHashMap, sample:

Map<String,String> map = new LinkedHashMap<String,String>();    
map.put(\'1\',\'linked\');map.put(\'1\',\'hash\');    
map.put(\'2\',\'map\');map.put(\'3\',\'java\');.. 

output:

keys: 1,1,2,3

values: linked,hash, map, java