如何获得GPS定位一次5分钟的Android？(How to get gps location on

您好有谁能够给我一个GET位置的示例代码，每五分钟，请我都试过，我可以通过cliking按钮获得位置一次，但我需要它来五分钟显示一次。

谢谢

这是我的代码：

public void checkLocation(View v) {

        //initialize location manager
        manager =  (LocationManager) getSystemService(Context.LOCATION_SERVICE);

        //check if GPS is enabled
        //if not, notify user with a toast
        if (!manager.isProviderEnabled(LocationManager.GPS_PROVIDER)) {
            Toast.makeText(this, "GPS is disabled.", Toast.LENGTH_SHORT).show();
        } else {

            //get a location provider from location manager
            //empty criteria searches through all providers and returns the best one
            String providerName = manager.getBestProvider(new Criteria(), true);
            Location location = manager.getLastKnownLocation(providerName);

            TextView tv = (TextView)findViewById(R.id.locationResults);
            if (location != null) {
                tv.setText(location.getLatitude() + " latitude, " + location.getLongitude() + " longitude");
            } else {
                tv.setText("Last known location not found. Waiting for updated location...");
            }
            //sign up to be notified of location updates every 15 seconds - for production code this should be at least a minute
            manager.requestLocationUpdates(providerName, 15000, 1, this);
        }
    }

    @Override
    public void onLocationChanged(Location location) {
        TextView tv = (TextView)findViewById(R.id.locationResults);
        if (location != null) {
            tv.setText(location.getLatitude() + " latitude, " + location.getLongitude() + " longitude");
        } else {
            tv.setText("Problem getting location");
        }
    }

    @Override
    public void onProviderDisabled(String arg0) {}

    @Override
    public void onProviderEnabled(String arg0) {}

    @Override
    public void onStatusChanged(String arg0, int arg1, Bundle arg2) {}

    // Find the closest Bart Station
    public String findClosestBart(Location loc) {
        double lat = loc.getLatitude();
        double lon = loc.getLongitude();

        double curStatLat = 0;
        double curStatLon = 0;
        double shortestDistSoFar = Double.POSITIVE_INFINITY;
        double curDist;
        String curStat = null;
        String closestStat = null;

        //sort through all the stations
        // write some sort of for loop using the API.

        curDist = Math.sqrt( ((lat - curStatLat) * (lat - curStatLat)) +
                        ((lon - curStatLon) * (lon - curStatLon)) );
        if (curDist < shortestDistSoFar) {
            closestStat = curStat;
        }

        return closestStat;

        }   

Answer 1:

这里是获取位置，并设置监听GPS就几分钟和距离获得当前位置的代码，还我已经使用Runnable对象上每隔几分钟得到的位置。

Location gpslocation = null;

private static final int GPS_TIME_INTERVAL = 60000; // get gps location every 1 min
private static final int GPS_DISTANCE= 1000; // set the distance value in meter

/*
   for frequently getting current position then above object value set to 0 for both you will get continues location but it drown the battery
*/

private void obtainLocation(){
if(locMan==null)
    locMan = (LocationManager) getSystemService(LOCATION_SERVICE);

    if(locMan.isProviderEnabled(LocationManager.GPS_PROVIDER)){
        gpslocation = locMan.getLastKnownLocation(LocationManager.GPS_PROVIDER);
        if(isLocationListener){
             locMan.requestLocationUpdates(LocationManager.GPS_PROVIDER, 
                        GPS_TIME_INTERVAL, GPS_DISTANCE, GPSListener);
                }
            }
        }
}

现在，使用这种方法来获得当前位置和听众被要求每1分钟和1000米距离的位置变化。

为了得到每5分钟就可以使用该处理程序和可运行到设定好一段时间内得到这个位置：

private static final int HANDLER_DELAY = 1000*60*5;

Handler handler = new Handler();
handler.postDelayed(new Runnable() {
        public void run() {
            myLocation = obtainLocation();
            handler.postDelayed(this, HANDLER_DELAY);
        }
    }, START_HANDLER_DELAY);

这里是位置变化事件监听器GPS：

private LocationListener GPSListener = new LocationListener(){
    public void onLocationChanged(Location location) {
        // update location
        locMan.removeUpdates(GPSListener); // remove this listener
    }

    public void onProviderDisabled(String provider) {
    }

    public void onProviderEnabled(String provider) {
    }

    public void onStatusChanged(String provider, int status, Bundle extras) {
    }
};

您可以设置间隔时间为侦听器和处理程序一样为获得GPS定位。

Answer 2:

在使用中下面的计时器代码。

您可以使用下列选项中选择1这将让位置，如果移动移动百米。

    captureFrequencey=3*60*1000;   
LocationMngr.requestLocationUpdates(LocationManager.GPS_PROVIDER, captureFrequencey, 100, this);

看看这个链接http://developer.android.com/reference/android/location/LocationManager.html#requestLocationUpdates%28java.lang.String,%20long,%20float,%20android.location.LocationListener%29

选项2

   TimerTask refresher;
        // Initialization code in onCreate or similar:
        timer = new Timer();    
        refresher = new TimerTask() {
            public void run() {
              handler.sendEmptyMessage(0);
            };
        };
        // first event immediately,  following after 1 seconds each
        timer.scheduleAtFixedRate(refresher, 0,1000); 
        //=======================================================


final Handler handler = new Handler() {


        public void handleMessage(Message msg) {
              switch (msg.what) {
              case REFRESH: 
                  //your code here 

                  break;
              default:
                  break;
              }
          }
        };

计时器将调用处理程序的时间长度（1000变化到你所需要的时间）。

希望这会帮助你。

Answer 3:

我用可运行的这样做，

    final Runnable r = new Runnable() {
        public void run() {
    //Here add your code location listener call
    handler.postDelayed(this, 300000 );
        }
    };

    handler.postDelayed(r, 300000 );

Answer 4:

尝试这样的：

 private Handler handler = new Handler(); 

 handler.postDelayed(runnable, 300000);

 private Runnable runnable = new Runnable() {   
    public void run() {
        if (location != null) {

            onLocationChanged(location);
        } else {
            System.out.println("Location not avilable");
        }

        handler.postDelayed(this, 300000);
    } 
};

文章来源: How to get gps location once for 5 mins android?