I'm using Raspbian Wheezy, but this is not a Raspberry Pi specific question.
I am developing a C application, which allows the user to change their WiFi Password.
I did not find a ready script/command for this, so I'm trying to use sed.
I pass the SSID name and new key to a bash script, and the key is replaced for the that ssid block within *etc/wpa_supplicant/wpa_supplicant.conf.*.
My application runs as root.
A sample block is shown below.
network={
ssid="MY_SSID"
scan_ssid=1
psk="my_ssid_psk"
}
so far I've tried the following (I've copied the wpa_supplicant.conf to wpa.txt for trying) :
(1) This tries to do the replacement between a range, started when my SSID is detected, and ending when the closing brace, followed by a newline.
SSID="TRIMURTI"
PSK="12345678"
sed -n "1 !H;1 h;$ {x;/ssid=\"${SSID}\"/,/}\n/ s/[[:space:]]*psk=.*\n/\n psk=\"${PSK}\"\n/p;}" wpa.txt
and
(2) This tries to 'remember' the matched pattern, and reproduce it in the output, but with the new key.
SSID="TRIMURTI"
PSK="12345678"
sed -n "1 !H; 1 h;$ {x;s/\(ssid=\"${SSID}\".*psk=\).*\n/\1\"${PSK}\"/p;}" wpa.txt
I have used hold & pattern buffers as the pattern can span multiple lines.
Above, the first example seems to ignore the range & replaces the 1st instance, and then truncates the rest of the file.
The second example replaces the last found psk value & truncates the file thereafter.
So I need help in correcting the above code, or trying a different solution.