I'm trying to pass various strings into members of a Struct via pointer but I am doing something fundamentally incorrect. What I think is that it doesn't need to be dereferenced. The process below works for other types of data such as int or char. For example:
typedef struct Course {
string location[15];
string course[20];
string title[40];
string prof[40];
string focus[10];
int credit;
int CRN;
int section;
} Course;
void c_SetLocation(Course *d, string location){
d->location = location;
. . .
}
I get an error when I try to compile the following algorithm to initialize a Course:
void c_Init(Course *d, string &location, ... ){
c_SetLocation(d, location[]);
. . .
}
The error:
error: cannot convert ‘const char*’ to ‘std::string* {aka std::basic_string<char>*}’ for argument ‘2’ to ‘void c_Init(Course*, std::string*, ..
You're actually defining, for example, an array of 15 strings in the location field. Either use regular strings; e. g.:
typedef struct Course {
string location;
string course;
string title;
string prof;
string focus;
int credit;
int CRN;
int section;
} Course;
or use char arrays:
typedef struct Course {
char location[15];
char course[20];
char title[40];
char prof[40];
char focus[10];
int credit;
int CRN;
int section;
} Course;
When you declare char a[10], you're creating an array of 10 characters. When you declare an std::string, you're creating a string that can grow to arbitrary size. When you declare an std::string[15], you're creating an array of 15 strings that can grow to arbitrary size.
Here's what your struct should look like:
typedef struct Course {
std::string location;
std::string course;
std::string title;
std::string prof;
std::string focus;
int credit;
int CRN;
int section;
} Course;
string location[15] means that you want to create 15 instances of a string, and each of those individual instances can have any length of text.
Instead of d->location, you need to assign one of those 15 strings: d->location[0] = location, d->location[1] = location, etc.
