MongoDB Show all contents from all collections

2019-01-16 05:30发布

问题:

Is it possible to show all collections and its contents in MongoDB?

Is the only way to show one by one?

回答1:

Once you are in terminal/command line, access the database/collection you want to use as follows:

show dbs
use <db name>
show collections

choose your collection and type the following to see all contents of that collection:

db.collectionName.find()

More info here on the MongoDB Quick Reference Guide.



回答2:

Step 1: See all your databases:

show dbs

Step 2: Select the database

use your_database_name

Step 3: Show the collections

show collections

This will list all the collections in your selected database.

Step 4: See all the data

db.collection_name.find() 

or

db.collection_name.find().pretty()


回答3:

var collections = db.getCollectionNames();
for(var i = 0; i< collections.length; i++){    
   print('Collection: ' + collections[i]); // print the name of each collection
   db.getCollection(collections[i]).find().forEach(printjson); //and then print the json of each of its elements
}

I think this script might get what you want. It prints the name of each collection and then prints its elements in json.



回答4:

Before writing below queries first get into your cmd or PowerShell

TYPE:
mongo             //To get into MongoDB shell
use <Your_dbName>      //For Creating or making use of existing db

To List All Collection Names use any one from below options :-

show collections  //output every collection
  OR
show tables
  OR
db.getCollectionNames() //shows all collections as a list

To show all collections content or data use below listed code which had been posted by Bruno_Ferreira.

var collections = db.getCollectionNames();
for(var i = 0; i< collections.length; i++) {    
   print('Collection: ' + collections[i]); // print the name of each collection
   db.getCollection(collections[i]).find().forEach(printjson); //and then print     the json of each of its elements
}


回答5:

This way:

db.collection_name.find().toArray().then(...function...)