I have a SQL column with a length of 6. Now want to take only the first char of that column. Is there any string function in SQL to do this?
问题:
回答1:
LEFT(colName, 1)
will also do this, also. It's equivalent to SUBSTRING(colName, 1, 1)
.
I like LEFT
, since I find it a bit cleaner, but really, there's no difference either way.
回答2:
I prefer:
SUBSTRING (my_column, 1, 1)
because it is Standard SQL-92 syntax and therefore more portable.
Strictly speaking, the standard version would be
SUBSTRING (my_column FROM 1 FOR 1)
The point is, transforming from one to the other, hence to any similar vendor variation, is trivial.
p.s. It was only recently pointed out to me that functions in standard SQL are deliberately contrary, by having parameters lists that are not the conventional commalists, in order to make them easily identifiable as being from the standard!
回答3:
SUBSTRING ( MyColumn, 1 , 1 )
for the first character and SUBSTRING ( MyColumn, 1 , 2 )
for the first two.
回答4:
It is simple to achieve this by following:
DECLARE @SomeString NVARCHAR(20) = 'This is some string'
DECLARE @Result NVARCHAR(20)
and either
SET @Result = SUBSTRING(@SomeString, 2, 3)
SELECT @Result
@Result: his
-OR-
SET @Result = LEFT(@SomeString, 6)
SELECT @Result
@Result: This i
回答5:
SELECT SUBSTR(thatColumn, 1, 1) As NewColumn from student
回答6:
INPUT
STRMIDDLENAME
--------------
Aravind Chaterjee
Shivakumar
Robin Van Parsee
SELECT STRMIDDLENAME,
CASE WHEN INSTR(STRMIDDLENAME,' ',1,2) != 0 THEN SUBSTR(STRMIDDLENAME,1,1) || SUBSTR(STRMIDDLENAME,INSTR(STRMIDDLENAME,' ',1,1)+1,1)||
SUBSTR(STRMIDDLENAME,INSTR(STRMIDDLENAME,' ',1,2)+1,1)
WHEN INSTR(STRMIDDLENAME,' ',1,1) != 0 THEN SUBSTR(STRMIDDLENAME,1,1) || SUBSTR(STRMIDDLENAME,INSTR(STRMIDDLENAME,' ',1,1)+1,1)
ELSE SUBSTR(STRMIDDLENAME,1,1)
END AS FIRSTLETTERS
FROM Dual;
OUTPUT
STRMIDDLENAME FIRSTLETTERS
--------- -----------------
Aravind Chaterjee AC
Shivakumar S
Robin Van Parsee RVP
回答7:
If you search the first char of string in Sql string
SELECT CHARINDEX('char', 'my char')
=> return 4