I have a method with a handled exception:
public boolean exampleMethod(){
try{
Integer temp=null;
temp.equals(null);
return
}catch(Exception e){
e.printStackTrace();
}
}
I want to test it
public void test_exampleMethod(){}
I have tried
@Rule
public ExpectedException expectedException=ExpectedException.none();
public void test_exampleMethod(){
expectedException.expect(JsonParseException.class);
exampleMethod();
}
but that doesnt work because the exception is handled inside.
I also tried
@Test(expected=JsonParseException.class)
but same issue...the exception is handled
I know that I can just do
assertTrue(if(exampleMethod()))
but it will still print the stack trace to the log. I would prefer clean logs...Any suggestions?
You cannot test what a method is doing internally. This is completely hidden (unless there are side effects, that are visible outside).
The test can check that for a specific input the method returns a expected output. But you can not check, how this is done. So you have no way to detect if there was a exception that you have handled.
So: either don't handle the exception (let the test catch the exception), or return a special value that tells you about the exception.
Anyway, I hope your real exception handling is more sensible than in your example.
If the method does not throw an exception you cannot expect to get one!
Below an example how write a Junit Test for a method that throws an Exception:
class Parser {
public void parseValue(String number) {
return Integer.parseInt(number);
}
}
Normal test case
public void testParseValueOK() {
Parser parser = new Parser();
assertTrue(23, parser.parseValue("23"));
}
Test case for exception
public void testParseValueException() {
Parser parser = new Parser();
try {
int value = parser.parseValue("notANumber");
fail("Expected a NumberFormatException");
} catch (NumberFormatException ex) {
// as expected got exception
}
}