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问题:
Suppose I have 3 classes as follows (as this is an example, it will not compile!):
class Base
{
public:
Base(){}
virtual ~Base(){}
virtual void DoSomething() = 0;
virtual void DoSomethingElse() = 0;
};
class Derived1
{
public:
Derived1(){}
virtual ~Derived1(){}
virtual void DoSomething(){ ... }
virtual void DoSomethingElse(){ ... }
virtual void SpecialD1DoSomething{ ... }
};
class Derived2
{
public:
Derived2(){}
virtual ~Derived2(){}
virtual void DoSomething(){ ... }
virtual void DoSomethingElse(){ ... }
virtual void SpecialD2DoSomething{ ... }
};
I want to create an instance of Derived1 or Derived2 depending on some setting that is not available until run-time.
As I cannot determine the derived type until run-time, then do you think the following is bad practice?...
class X
{
public:
....
void GetConfigurationValue()
{
....
// Get configuration setting, I need a "Derived1"
b = new Derived1();
// Now I want to call the special DoSomething for Derived1
(dynamic_cast<Derived1*>(b))->SpecialD1DoSomething();
}
private:
Base* b;
};
I have generally read that usage of dynamic_cast is bad, but as I said, I don't know
which type to create until run-time. Please help!
回答1:
Using dynamic_cast is not bad practice per se. It's bad practice to use it inappropriately, i.e. where it's not really needed.
It's also a bad practice to use it this way:
(dynamic_cast<Derived1*>(b))->SpecialD1DoSomething();
Reason: dynamic_cast(b) may return NULL.
When using dynamic_cast, you have to be extra careful, because it's not guaranteed, that b is actually of type Derived1 and not Derived2:
void GenericFunction(Base* p)
{
(dynamic_cast<Derived1*>(b))->SpecialD1DoSomething();
}
void InitiallyImplementedFunction()
{
Derived1 d1;
GenericFunction(&d1); // OK... But not for long.
// Especially, if implementation of GenericFunction is in another library
// with not source code available to even see its implementation
// -- just headers
}
void SomeOtherFunctionProbablyInAnotherUnitOfCompilation()
{
Derived2 d2;
GenericFunction(&d2); // oops!
}
You have to check if dynamic_cast is actually successful. There are two ways of doing it: checking it before and after the cast. Before the cast you can check if the pointer you're trying to cast is actually the one you expect via RTTI:
if (typeid(b) == typeid(Derived1*))
{
// in this case it's safe to call the function right
// away without additional checks
dynamic_cast<Derived1*>(b)->SpecialD1DoSomething();
}
else
{
// do something else, like try to cast to Derived2 and then call
// Derived2::SpecialD2DoSomething() in a similar fashion
}
Checking it post-factum is actually a bit simpler:
Derived1* d1 = dynamic_cast<Derived1*>(b);
if (d1 != NULL)
{
d1->SpecialD1DoSomething();
}
I'd also say it's a bad practice to try and save typing while programming in C++. There are many features in C++ than seem to be completely fine to be typed shorter (i.e. makes you feel 'that NULL will never happen here'), but turn out to be a pain in the ass to debug afterwards. ;)
回答2:
Why not delay the moment at which you "throw away" some if the type information by assigning a pointer to derived to a pointer to base:
void GetConfigurationValue()
{
// ...
// Get configuration setting, I need a "Derived1"
Derived1* d1 = new Derived1();
b = d1;
// Now I want to call the special DoSomething for Derived1
d1->SpecialD1DoSomething();
}
回答3:
The point of virtual functions is that once you have the right kind of object, you can call the right function without knowing which derived class this object is -- you just call the virtual function, and it does the right thing.
You only need a dynamic_cast
when you have a derived class that defines something different that's not present in the base class, and you need/want to take the extra something into account.
For example:
struct Base {
virtual void do_something() {}
};
struct Derived : Base {
virtual void do_something() {} // override dosomething
virtual void do_something_else() {} // add a new function
};
Now, if you just want to call do_something()
, a dynamic_cast
is completely unnecessary. For example, you can have a collection of Base *
, and just invoke do_something()
on every one, without paying any attention to whether the object is really a Base
or a Derived
.
When/if you have a Base *
, and you want to invoke do_something_else()
, then you can use a dynamic_cast
to figure out whether the object itself is really a Derived
so you can invoke that.
回答4:
Some other things you might like to consider to avoid the use of dynamic_cast
From Effective C++ (Third Edition) - Item 35 Alternatives to virtual functions -
- 'Template Method pattern' via Non-Vitual Interface (NVI). Making the virtual functions private/protected with a public method 'wrapper' - allows you to enforce some other workflow of stuff to do before and after the virtual method.
- 'Strategy pattern' via function pointers. Pass in the extra method as a function pointer.
- 'Strategy pattern' via tr1::function. similar to 2. but you could provide whole classes with various options
- 'Strategy pattern' classic. Seperate Strategy from main class - push the virtual functions into another hierarchy.
回答5:
There is a pattern named Factory Pattern that would fit this scenario. This allows you to return an instance of the correct class based on some input parameter.
Enjoy!
回答6:
What is wrong with:
Base * b;
if( some_condition ) {
b = new Derived1;
}
else {
b = new Derived2;
}
if ( Derived2 * d2 = dynamic_cast <Derived2 *>( b ) ) {
d2->SpecialD2DoSomething();
}
Or am I missing something?
And can OI suggest that when posting questions like this you (and others) name your classes A, B, C etc. and your functions things like f1(), f2() etc. It makes life a lot easier for people answering your questions.
回答7:
One way to avoid dynamic_cast
is to have a virtual trampoline function "SpecialDoSomething" whose derived polymorphic implementation calls that particular derived class's "SpecialDxDoSomething()" which can be whatever non-base class name you desire. It can even call more than one function.