Java, Spring 3.0.5 integrating with Apache tiles 2

问题:

Following this tutorial: http://viralpatel.net/blogs/2010/07/spring-3-mvc-tiles-plugin-tutorial-example-eclipse.html

Tiles configuration ( tiles.xml ) :

<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE tiles-definitions PUBLIC
       "-//Apache Software Foundation//DTD Tiles Configuration 2.1//EN"
       "http://tiles.apache.org/dtds/tiles-config_2_1.dtd">
<tiles-definitions>
    <definition name="base.definition"
        template="/WEB-INF/jsp/layout.jsp">
        <put-attribute name="title" value="" />
        <put-attribute name="header" value="/WEB-INF/jsp/header.jsp" />
        <put-attribute name="menu" value="/WEB-INF/jsp/menu.jsp" />
        <put-attribute name="body" value="" />
        <put-attribute name="footer" value="/WEB-INF/jsp/footer.jsp" />
    </definition>

    <definition name="contact" extends="base.definition">
        <put-attribute name="title" value="Contact Manager" />
        <put-attribute name="body" value="/WEB-INF/jsp/contact.jsp" />
    </definition>

</tiles-definitions>

spring-servlet.xml

<context:component-scan base-package="hello.spring3.controller" />

<bean id="viewResolver"
    class="org.springframework.web.servlet.view.UrlBasedViewResolver">
    <property name="viewClass" 
        value="org.springframework.web.servlet.view.tiles2.TilesView"/>
    <property name="prefix" value="/WEB-INF/jsp/"/>
    <property name="suffix" value=".jsp" />
</bean>

<bean id="tilesConfigurer"
    class="org.springframework.web.servlet.view.tiles2.TilesConfigurer">
    <property name="definitions">
        <list>
            <value>/WEB-INF/tiles.xml</value>
        </list>
    </property>
</bean>

when i run it, i get error: http://pastebin.com/KY541YKD

what could be the problem? if you have any questions about other files/configuration, ask me

回答1:

From your error:

java.lang.NoClassDefFoundError: org/apache/commons/digester/Rule

It looks like your missing a pre-3.0 version of commons-digester.