假设我有以下目录结构。
D:\reports\january\
一月内有假设两个Excel文件说A.xls和B.xls。 在有些情况下已经写了关于如何使用zip文件很多地方java.util.zip
。 但是,我要压缩报告文件夹中的文件夹一月本身,使1月和january.zip将出席内部报告。 ( 这意味着,当我解压january.zip文件我应该得到的一月文件夹 )。
任何人都可以请提供我的代码做到这一点使用java.util.zip
。 请让我知道这是否可以用其他图书馆更容易完成。
非常感谢...
Answer 1:
它可以通过包装可以轻松解决java.util.Zip
无需任何额外Jar
文件
只需复制下面的代码并run it
与你的IDE
//Import all needed packages
package general;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;
public class ZipUtils {
private List <String> fileList;
private static final String OUTPUT_ZIP_FILE = "Folder.zip";
private static final String SOURCE_FOLDER = "D:\\Reports"; // SourceFolder path
public ZipUtils() {
fileList = new ArrayList < String > ();
}
public static void main(String[] args) {
ZipUtils appZip = new ZipUtils();
appZip.generateFileList(new File(SOURCE_FOLDER));
appZip.zipIt(OUTPUT_ZIP_FILE);
}
public void zipIt(String zipFile) {
byte[] buffer = new byte[1024];
String source = new File(SOURCE_FOLDER).getName();
FileOutputStream fos = null;
ZipOutputStream zos = null;
try {
fos = new FileOutputStream(zipFile);
zos = new ZipOutputStream(fos);
System.out.println("Output to Zip : " + zipFile);
FileInputStream in = null;
for (String file: this.fileList) {
System.out.println("File Added : " + file);
ZipEntry ze = new ZipEntry(source + File.separator + file);
zos.putNextEntry(ze);
try {
in = new FileInputStream(SOURCE_FOLDER + File.separator + file);
int len;
while ((len = in .read(buffer)) > 0) {
zos.write(buffer, 0, len);
}
} finally {
in.close();
}
}
zos.closeEntry();
System.out.println("Folder successfully compressed");
} catch (IOException ex) {
ex.printStackTrace();
} finally {
try {
zos.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
public void generateFileList(File node) {
// add file only
if (node.isFile()) {
fileList.add(generateZipEntry(node.toString()));
}
if (node.isDirectory()) {
String[] subNote = node.list();
for (String filename: subNote) {
generateFileList(new File(node, filename));
}
}
}
private String generateZipEntry(String file) {
return file.substring(SOURCE_FOLDER.length() + 1, file.length());
}
}
请参阅mkyong ..我改变了代码为当前问题的规定
Answer 2:
您是否尝试过Zeroturnaround邮编库? 这真是整洁! 邮编文件夹只是一个班轮:
ZipUtil.pack(new File("D:\\reports\\january\\"), new File("D:\\reports\\january.zip"));
(感谢奥列格Šelajev为示例)
Answer 3:
这里是Java 8+例如:
public static void pack(String sourceDirPath, String zipFilePath) throws IOException {
Path p = Files.createFile(Paths.get(zipFilePath));
try (ZipOutputStream zs = new ZipOutputStream(Files.newOutputStream(p))) {
Path pp = Paths.get(sourceDirPath);
Files.walk(pp)
.filter(path -> !Files.isDirectory(path))
.forEach(path -> {
ZipEntry zipEntry = new ZipEntry(pp.relativize(path).toString());
try {
zs.putNextEntry(zipEntry);
Files.copy(path, zs);
zs.closeEntry();
} catch (IOException e) {
System.err.println(e);
}
});
}
}
Answer 4:
下面是这纯粹依赖于香草JDK类相当简洁的Java解决方案7+,不需要第三方库:
public static void pack(final Path folder, final Path zipFilePath) throws IOException {
try (
FileOutputStream fos = new FileOutputStream(zipFilePath.toFile());
ZipOutputStream zos = new ZipOutputStream(fos)
) {
Files.walkFileTree(folder, new SimpleFileVisitor<Path>() {
public FileVisitResult visitFile(Path file, BasicFileAttributes attrs) throws IOException {
zos.putNextEntry(new ZipEntry(folder.relativize(file).toString()));
Files.copy(file, zos);
zos.closeEntry();
return FileVisitResult.CONTINUE;
}
public FileVisitResult preVisitDirectory(Path dir, BasicFileAttributes attrs) throws IOException {
zos.putNextEntry(new ZipEntry(folder.relativize(dir).toString() + "/"));
zos.closeEntry();
return FileVisitResult.CONTINUE;
}
});
}
}
它将所有文件folder
,包括空目录,并建立在一个zip压缩包zipFilePath
。
Answer 5:
Java的7+,commons.io
public final class ZipUtils {
public static void zipFolder(final File folder, final File zipFile) throws IOException {
zipFolder(folder, new FileOutputStream(zipFile));
}
public static void zipFolder(final File folder, final OutputStream outputStream) throws IOException {
try (ZipOutputStream zipOutputStream = new ZipOutputStream(outputStream)) {
processFolder(folder, zipOutputStream, folder.getPath().length() + 1);
}
}
private static void processFolder(final File folder, final ZipOutputStream zipOutputStream, final int prefixLength)
throws IOException {
for (final File file : folder.listFiles()) {
if (file.isFile()) {
final ZipEntry zipEntry = new ZipEntry(file.getPath().substring(prefixLength));
zipOutputStream.putNextEntry(zipEntry);
try (FileInputStream inputStream = new FileInputStream(file)) {
IOUtils.copy(inputStream, zipOutputStream);
}
zipOutputStream.closeEntry();
} else if (file.isDirectory()) {
processFolder(file, zipOutputStream, prefixLength);
}
}
}
}
Answer 6:
我通常使用一个辅助类,我曾经写过这个任务:
import java.util.zip.*;
import java.io.*;
public class ZipExample {
public static void main(String[] args){
ZipHelper zippy = new ZipHelper();
try {
zippy.zipDir("folderName","test.zip");
} catch(IOException e2) {
System.err.println(e2);
}
}
}
class ZipHelper
{
public void zipDir(String dirName, String nameZipFile) throws IOException {
ZipOutputStream zip = null;
FileOutputStream fW = null;
fW = new FileOutputStream(nameZipFile);
zip = new ZipOutputStream(fW);
addFolderToZip("", dirName, zip);
zip.close();
fW.close();
}
private void addFolderToZip(String path, String srcFolder, ZipOutputStream zip) throws IOException {
File folder = new File(srcFolder);
if (folder.list().length == 0) {
addFileToZip(path , srcFolder, zip, true);
}
else {
for (String fileName : folder.list()) {
if (path.equals("")) {
addFileToZip(folder.getName(), srcFolder + "/" + fileName, zip, false);
}
else {
addFileToZip(path + "/" + folder.getName(), srcFolder + "/" + fileName, zip, false);
}
}
}
}
private void addFileToZip(String path, String srcFile, ZipOutputStream zip, boolean flag) throws IOException {
File folder = new File(srcFile);
if (flag) {
zip.putNextEntry(new ZipEntry(path + "/" +folder.getName() + "/"));
}
else {
if (folder.isDirectory()) {
addFolderToZip(path, srcFile, zip);
}
else {
byte[] buf = new byte[1024];
int len;
FileInputStream in = new FileInputStream(srcFile);
zip.putNextEntry(new ZipEntry(path + "/" + folder.getName()));
while ((len = in.read(buf)) > 0) {
zip.write(buf, 0, len);
}
}
}
}
}
Answer 7:
增强的Java 8+例如(从叉形尼基塔Koksharov的答案 )
public static void pack(String sourceDirPath, String zipFilePath) throws IOException {
Path p = Files.createFile(Paths.get(zipFilePath));
Path pp = Paths.get(sourceDirPath);
try (ZipOutputStream zs = new ZipOutputStream(Files.newOutputStream(p));
Stream<Path> paths = Files.walk(pp)) {
paths
.filter(path -> !Files.isDirectory(path))
.forEach(path -> {
ZipEntry zipEntry = new ZipEntry(pp.relativize(path).toString());
try {
zs.putNextEntry(zipEntry);
Files.copy(path, zs);
zs.closeEntry();
} catch (IOException e) {
System.err.println(e);
}
});
}
}
Files.walk
已经被包裹在try with resources
块,使得流可以被关闭。 这样就解决了通过鉴定拦截问题SonarQube
。 感谢@马特·哈里森指出这。
Answer 8:
我将使用Apache Ant的 ,其中有一个API从Java代码,而不是从XML构建文件调用的任务。
Project p = new Project();
p.init();
Zip zip = new Zip();
zip.setProject(p);
zip.setDestFile(zipFile); // a java.io.File for the zip you want to create
zip.setBasedir(new File("D:\\reports"));
zip.setIncludes("january/**");
zip.perform();
在这里,我告诉它从根目录开始D:\reports
,并拉上拉链的january
里面的文件夹和一切。 在所得到的压缩文件的路径将是相同的为相对于原始路径D:\reports
,所以他们将包括january
前缀。
Answer 9:
试试这个:
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;
public class Zip {
public static void main(String[] a) throws Exception {
zipFolder("D:\\reports\\january", "D:\\reports\\january.zip");
}
static public void zipFolder(String srcFolder, String destZipFile) throws Exception {
ZipOutputStream zip = null;
FileOutputStream fileWriter = null;
fileWriter = new FileOutputStream(destZipFile);
zip = new ZipOutputStream(fileWriter);
addFolderToZip("", srcFolder, zip);
zip.flush();
zip.close();
}
static private void addFileToZip(String path, String srcFile, ZipOutputStream zip)
throws Exception {
File folder = new File(srcFile);
if (folder.isDirectory()) {
addFolderToZip(path, srcFile, zip);
} else {
byte[] buf = new byte[1024];
int len;
FileInputStream in = new FileInputStream(srcFile);
zip.putNextEntry(new ZipEntry(path + "/" + folder.getName()));
while ((len = in.read(buf)) > 0) {
zip.write(buf, 0, len);
}
}
}
static private void addFolderToZip(String path, String srcFolder, ZipOutputStream zip)
throws Exception {
File folder = new File(srcFolder);
for (String fileName : folder.list()) {
if (path.equals("")) {
addFileToZip(folder.getName(), srcFolder + "/" + fileName, zip);
} else {
addFileToZip(path + "/" + folder.getName(), srcFolder + "/" + fileName, zip);
}
}
}
}
Answer 10:
Java的6 +
import java.io.*;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;
public class Zip {
private static final FileFilter FOLDER_FILTER = new FileFilter() {
@Override
public boolean accept(File pathname) {
return pathname.isDirectory();
}
};
private static final FileFilter FILE_FILTER = new FileFilter() {
@Override
public boolean accept(File pathname) {
return pathname.isFile();
}
};
private static void compress(File file, ZipOutputStream outputStream, String path) throws IOException {
if (file.isDirectory()) {
File[] subFiles = file.listFiles(FILE_FILTER);
if (subFiles != null) {
for (File subFile : subFiles) {
compress(subFile, outputStream, new File(path, subFile.getName()).getAbsolutePath());
}
}
File[] subDirs = file.listFiles(FOLDER_FILTER);
if (subDirs != null) {
for (File subDir : subDirs) {
compress(subDir, outputStream, new File(path, subDir.getName()).getAbsolutePath());
}
}
} else if (file.exists()) {
outputStream.putNextEntry(new ZipEntry(path));
FileInputStream inputStream = new FileInputStream(file);
byte[] buffer = new byte[1024];
int len;
while ((len = inputStream.read(buffer)) >= 0) {
outputStream.write(buffer, 0, len);
}
outputStream.closeEntry();
}
}
public static void compress(String dirPath, String zipFilePath) throws IOException {
File file = new File(dirPath);
final ZipOutputStream outputStream = new ZipOutputStream(new FileOutputStream(zipFilePath));
compress(file, outputStream, "/");
outputStream.close();
}
}
Answer 11:
我发现这个解决方案工作完美对我很好。 不需要任何第三方的API
“测试”实际上是一个文件夹,将大量的文件里。
String folderPath= "C:\Users\Desktop\test";
String zipPath = "C:\Users\Desktop\test1.zip";
private boolean zipDirectory(String folderPath, String zipPath) throws IOException{
byte[] buffer = new byte[1024];
FileInputStream fis = null;
ZipOutputStream zos = null;
try{
zos = new ZipOutputStream(new FileOutputStream(zipPath));
updateSourceFolder(new File(folderPath));
if (sourceFolder == null) {
zos.close();
return false;
}
generateFileAndFolderList(new File(folderPath));
for (String unzippedFile: fileList) {
System.out.println(sourceFolder + unzippedFile);
ZipEntry entry = new ZipEntry(unzippedFile);
zos.putNextEntry(entry);
if ((unzippedFile.substring(unzippedFile.length()-1)).equals(File.separator))
continue;
try{
fis = new FileInputStream(sourceFolder + unzippedFile);
int len=0;
while ((len = fis.read(buffer))>0) {
zos.write(buffer,0,len);
}
} catch(IOException e) {
return false;
} finally {
if (fis != null)
fis.close();
}
}
zos.closeEntry();
} catch(IOException e) {
return false;
} finally {
zos.close();
fileList = null;
sourceFolder = null;
}
return true;
}
private void generateFileAndFolderList(File node) {
if (node.isFile()) {
fileList.add(generateZipEntry(node.getAbsoluteFile().toString()));
}
if (node.isDirectory()) {
String dir = node.getAbsoluteFile().toString();
fileList.add(dir.substring(sourceFolder.length(), dir.length()) + File.separator);
String[] subNode = node.list();
for (String fileOrFolderName : subNode) {
generateFileAndFolderList(new File(node, fileOrFolderName));
}
}
}
private void updateSourceFolder(File node) {
if (node.isFile() || node.isDirectory()) {
String sf = node.getAbsoluteFile().toString();
sourceFolder = sf.substring(0, (sf.lastIndexOf("/") > 0 ? sf.lastIndexOf("/") : sf.lastIndexOf("\\")));
sourceFolder += File.separator;
} else
sourceFolder = null;
}
private String generateZipEntry(String file) {
return file.substring(sourceFolder.length(), file.length());
}
Answer 12:
这种方法呼啸而过文件夹,并将所有子文件和文件夹(包括空文件夹)的成zip文件。
void zipFolder(Path sourceDir, Path targetFile) throws IOException {
ZipDirectoryVisitor zipVisitor = new ZipDirectoryVisitor(sourceDir);
Files.walkFileTree(sourceDir, zipVisitor);
FileOutputStream fos = new FileOutputStream(targetFile.toString());
ZipOutputStream zos = new ZipOutputStream(fos);
byte[] buffer = new byte[1024];
for (ZipEntry entry : zipVisitor.getZipEntries()) {
zos.putNextEntry(entry);
Path curFile = Paths.get(sourceDir.getParent().toString(), entry.toString());
if (!curFile.toFile().isDirectory()) {
FileInputStream in = new FileInputStream(Paths.get(sourceDir.getParent().toString(), entry.toString()).toString());
int len;
while ((len = in.read(buffer)) > 0) {
zos.write(buffer, 0, len);
}
in.close();
}
zos.closeEntry();
}
zos.close();
}
这里是ZipDirectoryVisitor实现:
class ZipDirectoryVisitor extends SimpleFileVisitor<Path> {
private Path dirToZip;
private List<ZipEntry> zipEntries; // files and folders inside source folder as zip entries
public ZipDirectoryVisitor(Path dirToZip) throws IOException {
this.dirToZip = dirToZip;
zipEntries = new ArrayList<>();
}
@Override
public FileVisitResult visitFile(Path path, BasicFileAttributes basicFileAttributes) throws IOException {
// According to zip standard backslashes
// should not be used in zip entries
String zipFile = dirToZip.getParent().relativize(path).toString().replace("\\", "/");
ZipEntry entry = new ZipEntry(zipFile);
zipEntries.add(entry);
return FileVisitResult.CONTINUE;
}
@Override
public FileVisitResult preVisitDirectory(Path path, BasicFileAttributes basicFileAttributes) throws IOException {
String zipDir = dirToZip.getParent().relativize(path).toString().replace("\\", "/");
// Zip directory entries should end with a forward slash
ZipEntry entry = new ZipEntry(zipDir + "/");
zipEntries.add(entry);
return FileVisitResult.CONTINUE;
}
@Override
public FileVisitResult visitFileFailed(Path path, IOException e) throws IOException {
System.err.format("Could not visit file %s while creating a file list from file tree", path);
return FileVisitResult.TERMINATE;
}
public List<ZipEntry> getZipEntries() {
return zipEntries;
}
}
文章来源: how to zip a folder itself using java