I am trying to find the mean differences between my variable stim_ending_t which contains the following 6 factors: 1, 1.5, 2, 2.5, 3, 3.5
You can access the df Here
stim_ending_t visbility soundvolume Opening_text m sd coefVar
<dbl> <dbl> <dbl> <chr> <dbl> <dbl> <dbl>
1 1 0 0 Now focus on the Image 1.70 1.14 0.670
2 1 0 0 Now focus on the Sound 1.57 0.794 0.504
3 1 0 1 Now focus on the Image 1.55 1.09 0.701
4 1 0 1 Now focus on the Sound 1.77 0.953 0.540
5 1 1 0 Now focus on the Image 1.38 0.859 0.621
6 1 1 0 Now focus on the Sound 1.59 0.706 0.444
7 1.5 0 0 Now focus on the Image 1.86 0.718 0.387
8 1.5 0 0 Now focus on the Sound 2.04 0.713 0.350
9 1.5 0 1 Now focus on the Image 1.93 1.00 0.520
10 1.5 0 1 Now focus on the Sound 2.14 0.901 0.422
Here is a visual representation of my data
Q: How I can do ANOVA with the condition of comparing the mean by "Opening_test" which contains "Now focus on the Image", and "Now focus on the Sound."
Q: Also I want to follow that with post hoc test.
Here is what I have tried but apparently is not the right way!
# Compute one-way ANOVA test
res.aov <- aov(m ~ stim_ending_t, data = clean_test_master2)
summary(res.aov)
Df Sum Sq Mean Sq F value Pr(>F)
stim_ending_t 1 7.589 7.589 418.8 <2e-16 ***
Residuals 34 0.616 0.018
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
I think there is something wrong with result from aov! stim_ending_t has 6 factors, so Dgree of fredom (Df) should = 5 not != 1 from the above table.
# post hoc test
TukeyHSD(res.aov, conf.level = 0.99)
Here is the message I got
Error in TukeyHSD.aov(res.aov, conf.level = 0.99) :
no factors in the fitted model
In addition: Warning message:
In replications(paste("~", xx), data = mf) :
non-factors ignored: stim_ending_t
Note: the participants completed the experiment at one session by starting with either condition-Opening_text, randomly and completing the other one.