I asked in Any servers with open tcp ports known? about open tcp ports on websites and was told that stackoverflow itself has tcp port 80 open. I executed my program and it kind of misbehaved.
import optparse
from socket import *
from threading import *
screenLock = Semaphore(value=1)
def connScan(tgtHost, tgtPort):
try:
connSkt = Socket(AF_INET, SOCK_STREAM)
connSkt.connect((tgtHost, tgtPort))
connSkt.send('ExploitMessage\r\n')
results = connSkt.recv(100)
screenLock.acquire()
print('[+]%d/tcpopen'%tgtPort)
print('[+] ' + str(results))
connSkt.close()
except:
screenLock.acquire()
print('[-]%d/tcp closed'%tgtPort)
finally:
screenLock.release()
def portScan(tgtHost, tgtPorts):
try:
tgtIP = gethostbyname(tgtHost)
except:
print("[-] Cannot resolve '%s': Unknown host"%tgtHost)
return
try:
tgtName = gethostbyaddr(tgtIP)
print("\n[+] Scan results for: " + tgtName[0] + ' , ' + tgtIP)
except:
print("\n[+] Scan results for " + tgtIP)
setdefaulttimeout(1)
for tgtPort in tgtPorts:
t = Thread(target=connScan, args=(tgtHost, int(tgtPort)))
t.start()
def main():
parser = optparse.OptionParser('usage%prog ' + ' -H <target host> -p <target port>')
parser.add_option('-H', dest='tgtHost', type='string', help='specify target Host')
parser.add_option('-p', dest='tgtPort', type='string', help='specify target port[s] separated by comma')
(options, args) = parser.parse_args()
tgtHost = options.tgtHost
tgtPorts = str(options.tgtPort).split(',')
if ((tgtHost == None) | (tgtPorts[0]==None)):
print(parser.usage)
exit(0)
portScan(tgtHost, tgtPorts)
if __name__ == "__main__":
main()
Ths is my entire code. It does properly give me the "real" name of stackoverflow but says the tcp port would be closed. What am I doing wrong? I have tried it with other sites that should have a certain port open, but it always claims the port would be closed.
This is the output in the command shell:
[+] Scan results for: li547-15.members.linode.com , 198.74.50.15
[-]80/tcp closed
Please tell m why it's not working.