我想说的输出线5 - 10的文件，作为参数传入。
我怎么会用head和tail做到这一点？
其中firstline = $2和lastline = $3和filename = $1 。
运行它应该是这样的：
./lines.sh filename firstline lastline
Answer 1:
除了给出的答案fedorqui和肯特 ，你也可以使用一个单一的sed命令：
#! /bin/sh
filename=$1
firstline=$2
lastline=$3
# Basics of sed:
# 1. sed commands have a matching part and a command part.
# 2. The matching part matches lines, generally by number or regular expression.
# 3. The command part executes a command on that line, possibly changing its text.
#
# By default, sed will print everything in its buffer to standard output.
# The -n option turns this off, so it only prints what you tell it to.
#
# The -e option gives sed a command or set of commands (separated by semicolons).
# Below, we use two commands:
#
# ${firstline},${lastline}p
# This matches lines firstline to lastline, inclusive
# The command 'p' tells sed to print the line to standard output
#
# ${lastline}q
# This matches line ${lastline}. It tells sed to quit. This command
# is run after the print command, so sed quits after printing the last line.
#
sed -ne "${firstline},${lastline}p;${lastline}q" < ${filename}
或者，为了避免任何外部UTILITES，如果你使用的是最新的bash（或zsh中）的版本：
#! /bin/sh
filename=$1
firstline=$2
lastline=$3
i=0
exec <${filename} # redirect file into our stdin
while read ; do # read each line into REPLY variable
i=$(( $i + 1 )) # maintain line count
if [ "$i" -ge "${firstline}" ] ; then
if [ "$i" -gt "${lastline}" ] ; then
break
else
echo "${REPLY}"
fi
fi
done
Answer 2:
head -n XX # <-- print first XX lines
tail -n YY # <-- print last YY lines
如果你想从20线30，这意味着你需要11条线路从20日开始，在30后整理：
head -n 30 file | tail -n 11
#
# first 30 lines
# last 11 lines from those previous 30
也就是说，你首先得先30线，然后选择最后11 （即30-20+1 ）。
因此，在你的代码将是：
head -n $3 $1 | tail -n $(( $3-$2 + 1 ))
基于firstline = $2 ， lastline = $3 ， filename = $1
head -n $lastline $filename | tail -n $(( $lastline -$firstline + 1 ))
Answer 3:
试试这个班轮：
awk -vs="$begin" -ve="$end" 'NR>=s&&NR<=e' "$f"
在上面的行：
$begin is your $2
$end is your $3
$f is your $1
Answer 4:
Save this as "script.sh":
#!/bin/sh
filename="$1"
firstline=$2
lastline=$3
linestoprint=$(($lastline-$firstline+1))
tail -n +$firstline "$filename" | head -n $linestoprint
There is NO ERROR HANDLING (for simplicity) so you have to call your script as following:
./script.sh yourfile.txt firstline lastline
$ ./script.sh yourfile.txt 5 10
If you need only line "10" from yourfile.txt:
$ ./script.sh yourfile.txt 10 10
Please make sure that: (firstline > 0) AND (lastline > 0) AND (firstline <= lastline)
文章来源: How do I use Head and Tail to print specific lines of a file
