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问题:
If a user enters a string: hello there
it should output
Hello has 2 vowels
There has 3 consonants.
I know this is a fairly simple code but I am getting too many ideas and getting confused.
I need a to make sure I have 2 methods for numberofVowels and capitalizeWord and both returns a result
I am getting an error and I am still trying to figure out to capitalize after I got counting vowels work
import java.util.Scanner;
public class Hwk9
{
public static void main (String args[])
{
Scanner stdin = new Scanner(System.in);
String string1;
System.out.println("Enter a string");
string1 = stdin.nextLine();
string1 = string1.toLowerCase();
}
public static int numberVowels(String string1)
{
int count = 0;
int vowels = 0;
int consonants = 0;
for (int i = 0; i < string1.length(); i++)
{
char ch = string1.charAt(i);
if (ch == 'a' || ch == 'e' || ch == 'i' ||
ch == 'o' || ch == 'u')
{
vowels++;
}
else
{
consonants++;
}
}
}
}
回答1:
Here is a simpler way of doing this, hope this helps:
public static void checkVowels(String s){
System.out.println("Vowel Count: " + (s.length() - s.toLowerCase().replaceAll("a|e|i|o|u|", "").length()));
//Also eliminating spaces, if any for the consonant count
System.out.println("Consonant Count: " + (s.toLowerCase().replaceAll("a|e|i|o| |u", "").length()));
}
回答2:
Made something like this hope this helps, this will give vowels,consonants of each word
public static void main (String args[])
{
Scanner stdin = new Scanner(System.in);
String string1;
System.out.println("Enter a string");
string1 = stdin.nextLine();
string1 = string1.toLowerCase();
int count = 0;
int vowels = 0;
int consonants = 0;
for (String retval: string1.split(" ")){
for (int i = 0; i < retval.length(); i++)
{
char ch = retval.charAt(i);
if (ch == 'a' || ch == 'e' || ch == 'i' ||
ch == 'o' || ch == 'u')
{
vowels++;
}
else
{
consonants++;
}
}
System.out.println(retval.substring(0, 1).toUpperCase() + retval.substring(1)+" has "+vowels+" vowels and "+consonants+" cosonants");
vowels=0;
consonants=0;
}
}
回答3:
My code without scanner and maybe not very simple, but:
public class Main{
public static void main(String[] args) {
String test = "qwertyYVTA";
test = test.trim();
int vowels = 0;
int consonants = 0;
Pattern patternVow = Pattern.compile("[eyuioa]", Pattern.CASE_INSENSITIVE | Pattern.UNICODE_CASE);
Matcher matcherVow = patternVow.matcher(test);
while (matcherVow.find()) {
vowels++;
}
Pattern patternCons = Pattern.compile("[wrtpsdfghjklzxcvbnm]", Pattern.CASE_INSENSITIVE | Pattern.UNICODE_CASE);
Matcher matcherCons = patternCons.matcher(test);
while (matcherCons.find()) {
consonants++;
}
System.out.println("Vowels in test String is " + vowels);
System.out.println("Consonants in test String is " + consonants);
}
}
回答4:
following code will give you vowel and Constonent count
static String VOWEL_GROUP = "AEIOUaeiou";
static String testString = "AAAASHMAIOUAXCCDIOUGGGGA"; // say this is your text
public static void main(String[] args) {
int vovelCount = 0;
int consonantCount = 0;
for (int j = testString.length() - 1; j >= 0; j--) {//outer loop
for (int i = 0; i < VOWEL_GROUP.length(); i++) { //inner loop
if (VOWEL_GROUP.charAt(i) == testString.charAt(j)) {
vovelCount++; //vowel count in text
break;
}else{
consonantCount ++;
}
}
}
System.out.println(vovelCount+" "+ consonantCount);
}
回答5:
I suggest you;
- to create a final vowels array,
- define a
bool isVowel(char c)
function and use it in your if condition.
回答6:
Here is the simple code for counting the number of vowels using recursion
public static int vowels(String s){
int count =0;
char c;
if(s.length()==0){
return 0;
}
else{
c =s.charAt(0);
if(c=='a'||c=='e'||c=='i'||c=='o'||c=='u'){
count++;
}
return count+vowels(s.substring(1));
}
}
回答7:
This looks way simple than above answers. It gets the input, converts it to lowercase then to an array of characters. A simple for loop will do the trick onwards.
import java.util.*;
public class FindVowelsConsonents {
public static void main(String[] args) {
int vowels_count = 0;
int consonents_count = 0;
Scanner sc = new Scanner(System.in);
String str = sc.nextLine();
String str2 = str.toLowerCase();
char[] chr = str2.toCharArray();
for(int i=0;i<chr.length;i++){
if(chr[i] == 'a' || chr[i]== 'e' || chr[i] == 'i' ||
chr[i] == 'o' || chr[i] == 'u')
vowels_count++;
else
consonents_count++;
}
System.out.println(vowels_count+ " "+consonents_count);
sc.close();
}
}
回答8:
As far as I am concerned you can use StringTokenizer:
String text = "dupalo twoja mama";
StringTokenizer tokenizer = new StringTokenizer(text,"aeiuo",false);
int vowels = tokenizer.countTokens();
System.out.println(vowels);
In this case of "text" it will print out 7.
回答9:
import java.util.Scanner;
//don't use space in between the input string;
class StrRev {
static String Vowels ="aeiouAEIOU";
public static void main(String[] args){
@SuppressWarnings("resource")
Scanner name = new Scanner(System.in);
String nm = name.nextLine();
System.out.println();
int vowel=0;
int consonant=0;
for(int i=0;i<nm.length();i++){
for(int j=0;j<Vowels.length();j++){
if(Vowels.charAt(j)==nm.charAt(i)){
vowel++;
break;
}
}
}
consonant = nm.length()-vowel;
System.out.println("no of Vowels :"+vowel+"\nno of consonant :"+consonant);
}
}