我有一个JSON对象,我想摆脱键名,并将它们存储在一个ArrayList。 我用下面的代码
jsonData(String filename) {
JsonParser parser = new JsonParser();
JsonElement jsonElement = null;
try {
jsonElement = parser.parse(new FileReader(filename));
} catch (JsonIOException | JsonSyntaxException | FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
JsonObject jsonObject = jsonElement.getAsJsonObject();
int i = 0;
for (Entry<String, JsonElement> entry : jsonObject.entrySet()) {
String key = entry.getKey();
JsonElement value = entry.getValue();
keys.add(key);
i++;
}
nKeys = i;
}
如果我用这个代码用一个简单的JSON对象
{
"age":100,
"name":"mkyong.com",
"messages":["msg 1","msg 2","msg 3"]
}
这工作得很好。 年龄,姓名和消息(不是值)被添加到我的ArrayList。 有一次,我尝试使用相同的代码,像这样一个比较复杂的JSON
{"widget": {
"debug": "on",
"window": {
"title": "Sample Konfabulator Widget",
"name": "main_window",
"width": 500,
"height": 500
},
"image": {
"src": "Images/Sun.png",
"name": "sun1",
"hOffset": 250,
"vOffset": 250,
"alignment": "center"
},
"text": {
"data": "Click Here",
"size": 36,
"style": "bold",
"name": "text1",
"hOffset": 250,
"vOffset": 100,
"alignment": "center",
"onMouseUp": "sun1.opacity = (sun1.opacity / 100) * 90;"
}
}}
我只得到根密钥。 有人能指出我在这个正确的方向?
感谢大家!
相反,通过与循环和条件的GSON(JSON)API蜿蜒的,我宁愿使用GSON什么,我认为它最擅长的:提供了非常简单的(反)序列化处理,只需几行代码。 我会去耦从(反)序列关心的任何数据操作/查询/表示担忧。 换句话说,尽可能合理,操作数据在必要时,序列化之前,同样,操作数据在必要时,反序列化之后。
因此,如果由于某种原因,我想所有的JSON结构的关键,我想用GSON,如下我有可能接近它。 (当然,我目前还不能想到的任何理由,这样的事情可能是有用的。)
import java.io.FileReader;
import java.util.ArrayList;
import java.util.Collection;
import java.util.List;
import java.util.Map;
import com.google.gson.Gson;
public class App
{
public static void main(String[] args) throws Exception
{
List keys1 = getKeysFromJson("input_without_lists.json");
System.out.println(keys1.size());
System.out.println(keys1);
List keys2 = getKeysFromJson("input_with_lists.json");
System.out.println(keys2.size());
System.out.println(keys2);
}
static List getKeysFromJson(String fileName) throws Exception
{
Object things = new Gson().fromJson(new FileReader(fileName), Object.class);
List keys = new ArrayList();
collectAllTheKeys(keys, things);
return keys;
}
static void collectAllTheKeys(List keys, Object o)
{
Collection values = null;
if (o instanceof Map)
{
Map map = (Map) o;
keys.addAll(map.keySet()); // collect keys at current level in hierarchy
values = map.values();
}
else if (o instanceof Collection)
values = (Collection) o;
else // nothing further to collect keys from
return;
for (Object value : values)
collectAllTheKeys(keys, value);
}
}
input_without_lists.json
{
"widget": {
"debug": "on",
"window": {
"title": "Sample Konfabulator Widget",
"name": "main_window",
"width": 500,
"height": 500
},
"image": {
"src": "Images/Sun.png",
"name": "sun1",
"hOffset": 250,
"vOffset": 250,
"alignment": "center"
},
"text": {
"data": "Click Here",
"size": 36,
"style": "bold",
"name": "text1",
"hOffset": 250,
"vOffset": 100,
"alignment": "center",
"onMouseUp": "sun1.opacity = (sun1.opacity / 100) * 90;"
}
}
}
input_with_lists.json
[{
"widget": {
"debug": "on",
"windows": [{
"title": "Sample Konfabulator Widget",
"name": "main_window",
"width": 500,
"height": 500
},{
"title": "Sample Konfabulator Widget",
"name": "main_window",
"width": 500,
"height": 500
},{
"title": "Sample Konfabulator Widget",
"name": "main_window",
"width": 500,
"height": 500
}]
}
}]