我们必须加载到Hadoop的一个名为XML的String列XML数据。 我们正试图获取到数据的规范化水平,或者它爆炸成单行进行处理(你知道,像表!)尝试过爆炸的功能,但没有得到我们想要的东西。
示例XML
<Reports>
<Report ID="1">
<Locations>
<Location ID="20001">
<LocationName>Irvine Animal Shelter</LocationName>
</Location>
<Location ID="20002">
<LocationName>Irvine City Hall</LocationName>
</Location>
</Locations>
</Report>
<Report ID="2">
<Locations>
<Location ID="10001">
<LocationName>California Fish Grill</LocationName>
</Location>
<Location ID="10002">
<LocationName>Fukada</LocationName>
</Location>
</Locations>
</Report>
</Reports>
查询1
我们正在查询从孩子(地址/位置)更高级别的Report.Id然后ID和名称。 下面让我们基本上所有可能的组合的笛卡尔积(在这个例子中,8行,而不是我们希望的4)。
SELECT xpath_int(xml, '/Reports/Report/@ID') AS id, location_id, location_name
FROM xmlreports
LATERAL VIEW explode(xpath(xml, '/Reports/Report/Locations/Location/@ID')) myTable1 AS location_id
LATERAL VIEW explode(xpath(xml, '/Reports/Report/Locations/Location/LocationName/text()')) myTable2 AS location_name;
查询2
试图组成结构,然后爆炸,但是这将返回两行和两列。
SELECT id, loc.col1, loc.col2
FROM (
SELECT xpath_int(xml, '/Reports/Report/@ID') AS id,
array(struct(xpath(xml, '/Reports/Report/Locations/Location/@ID'), xpath(xml, '/Reports/Report/Locations/Location/LocationName/text()'))) As foo
FROM xmlreports) x
LATERAL VIEW explode(foo) exploded_table as loc;
结果
1 ["20001","20002"] ["Irvine Animal Shelter","Irvine City Hall"]
2 ["10001","10002"] ["California Fish Grill","Irvine Spectrum"]
我们要的是
1 "20001" "Irvine Animal Shelter"
1 "20002" "Irvine City Hall"
2 "10001" "California Fish Grill"
2 "10002" "Irvine Spectrum"
似乎是一个常见的事想做,但找不到任何的例子。 任何帮助是极大的赞赏。