我要让所有由枢轴生产成为0的NULL值。 我已经把ISNULL在每一个地方想象,但似乎并没有产生任何影响。 是枢轴与ISNULL兼容? 下面的代码:
DECLARE @startDate datetime
SET @startDate = '2013-01-01'
DECLARE @sql varchar(MAX)
SET @sql = 'SELECT
CLIENTNAME, PROJECTNAME, RESOURCE, [' +
REPLACE(SUBSTRING(CONVERT(varchar, @startDate, 13), 4, 8), ' ', '') + '], [' +
REPLACE(SUBSTRING(CONVERT(varchar, DATEADD(MONTH, 1, @startDate), 13), 4, 8), ' ', '') + '], [' +
REPLACE(SUBSTRING(CONVERT(varchar, DATEADD(MONTH, 2, @startDate), 13), 4, 8), ' ', '') + '], [' +
REPLACE(SUBSTRING(CONVERT(varchar, DATEADD(MONTH, 3, @startDate), 13), 4, 8), ' ', '') + '], [' +
REPLACE(SUBSTRING(CONVERT(varchar, DATEADD(MONTH, 4, @startDate), 13), 4, 8), ' ', '') + '], [' +
REPLACE(SUBSTRING(CONVERT(varchar, DATEADD(MONTH, 5, @startDate), 13), 4, 8), ' ', '') + ']
FROM
(
SELECT
CLIENTNAME, PROJECTNAME, RESOURCE, FORECASTTOTAL
FROM viewprojscheduling_group
) AS SourceTable
PIVOT
(
SUM(FORECASTTOTAL)
FOR SCHEDULEDDATE IN (' +
QUOTENAME(REPLACE(SUBSTRING(CONVERT(varchar, @startDate, 13), 4, 8), ' ', '')) + ', ' +
QUOTENAME(REPLACE(SUBSTRING(CONVERT(varchar, DATEADD(MONTH, 1, @startDate), 13), 4, 8), ' ', '')) + ', ' +
QUOTENAME(REPLACE(SUBSTRING(CONVERT(varchar, DATEADD(MONTH, 2, @startDate), 13), 4, 8), ' ', '')) + ', ' +
QUOTENAME(REPLACE(SUBSTRING(CONVERT(varchar, DATEADD(MONTH, 3, @startDate), 13), 4, 8), ' ', '')) + ', ' +
QUOTENAME(REPLACE(SUBSTRING(CONVERT(varchar, DATEADD(MONTH, 4, @startDate), 13), 4, 8), ' ', '')) + ', ' +
QUOTENAME(REPLACE(SUBSTRING(CONVERT(varchar, DATEADD(MONTH, 5, @startDate), 13), 4, 8), ' ', '')) + ')
) AS PivotTable'
execute(@sql)
我会设置查询了略有不同,因为虽然它是动态的,列名正在发生变化,你仍然硬编码的列数。
首先,我会用递归CTE产生月/年要创建的列表。
DECLARE @startDate datetime
SET @startDate = '2013-01-01'
;with dates as
(
select @startdate datelist, 1 sp
union all
select dateadd(month, 1, datelist), sp+1
from dates
where sp+1 <= 5 -- change this number 5 to the number of months you need
)
select sp,
REPLACE(SUBSTRING(CONVERT(varchar(11), datelist, 13), 4, 8), ' ', '') MONTHANDYEAR
from dates
请参阅SQL拨弄演示 。 这将创建你的5个月,自动今年的榜单。 那么你就不是硬编码的5列。 您当前的查询不灵活,因为它可以。 会发生什么,如果你再想12个月中,你将不得不改变你的代码。
一旦你生成日期列表,我将它插入到一个临时表,所以你可以用它来获取列。
代码即可获得列的列表:
select @cols = STUFF((SELECT ',' + QUOTENAME(monthandyear)
from #datesTemp
group by monthandyear, sp
order by sp
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
select @colNames = STUFF((SELECT ', isnull(' + QUOTENAME(monthandyear)+', 0) as '+QUOTENAME(monthandyear)
from #datesTemp
group by monthandyear, sp
order by sp
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
请参阅SQL拨弄演示 。 你会看到,有两个版本。 第一个@cols
获取将在使用的列的列表pivot
。 第二@colNames
将在决赛中使用SELECT
列表更换null
与零值。
然后你把它放在一起,代码将是:(注:我使用的从你的版本我的回答前面的问题 )
DECLARE @cols AS NVARCHAR(MAX),
@colNames AS NVARCHAR(MAX),
@query AS NVARCHAR(MAX),
@startDate datetime
SET @startDate = '2013-01-01'
;with dates as
(
select @startdate datelist, 1 sp
union all
select dateadd(month, 1, datelist), sp+1
from dates
where sp+1 <= 5 -- change this number 5 to the number of months you need
)
select sp,
REPLACE(SUBSTRING(CONVERT(varchar(11), datelist, 13), 4, 8), ' ', '') MONTHANDYEAR
into #datesTemp
from dates
select @cols = STUFF((SELECT ',' + QUOTENAME(monthandyear)
from #datesTemp
group by monthandyear, sp
order by sp
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
select @colNames = STUFF((SELECT ', isnull(' + QUOTENAME(monthandyear)+', 0) as '+QUOTENAME(monthandyear)
from #datesTemp
group by monthandyear, sp
order by sp
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query = 'SELECT resource, clientname,' + @colNames + '
from
(
select [CLIENTNAME], [RESOURCE], [FORECASTTOTAL],
REPLACE(SUBSTRING(CONVERT(varchar(11), SCHEDULEDDATE, 13), 4, 8), '' '', '''') monthandyear
from viewprojscheduling_group
) x
pivot
(
sum(FORECASTTOTAL)
for monthandyear in (' + @cols + ')
) p '
execute(@query)
请参阅SQL拨弄演示 。 该查询会给你的结果:
| RESOURCE | CLIENTNAME | JAN2013 | FEB2013 | MAR2013 | APR2013 | MAY2013 |
---------------------------------------------------------------------------
| res1 | abc | 1000 | 2000 | 0 | 0 | 0 |
| res1 | def | 0 | 0 | 2000 | 0 | 0 |
| res2 | def | 1500 | 0 | 0 | 0 | 0 |
| res3 | ghi | 0 | 0 | 2500 | 0 | 0 |