Swagger create API document: Swagger Editor

问题:

I am using swagger for documenting my REST API service. I have an specific input that I provide to the service. I am creating YAML code by myself using swagger editor. The issue I am facing is I am not able to get the input type as XML, it by default takes JSON. Is there any issue in my yaml code. The code is given below:

swagger: "2.0"
info:
title: Order Update to Dealers
 description: API description in Markdown.
 version: 1.0.0
host: #Host name cannot be specified here
basePath: /api/OrderUpdate
schemes:
  - http
paths:
/GetFullOrderAcknowlegement:
post:
  summary: Returns a list of users.
  consumes: 
    - application/xml 
  produces:
    - text/plain

  parameters:
    - in: body
      name: DealerInput
      description: Optional extended description in Markdown.

      schema:
        properties:
          DealerID:
            type: string
          PONumber:
            type: string
  responses:
    201:
      description: Created
    200:
      schema: {}
      description: OK
    401:
      schema: {}
      description: Authorization information is missing or invalid.

回答1:

This was a bug in Swagger Editor 3.3.0 and Swagger UI 3.11.0. It was fixed in Editor 3.3.1 and UI 3.12.0 (released on March 4, 2018).

As a workaround, you can download Editor v3.2.9 and run it locally by opening the index.html file in your browser.