我的代码似乎没有工作..单选按钮出现,但没有他们身边..它看起来好像mysql_fetch_array不是出于某种原因的工作,因为我已经与代码发挥有关,并反复测试它寻找到的代码似乎遇到有问题而停止工作..可能有人请告知有什么不好? 欢呼声PS。 我是新在此,只完成了学习上W3Schools的最后几天php的教程。
<body>
<?php
include 'dbyear2.php';
$qnumber = $_REQUEST['uqn']; // obtain question number from URL
$find = mysql_query("SELECT * FROM Renal WHERE UQN='$qnumber'");
while($retrieve=mysql_fetch_array($find));
{
$retrieve['question'] = $question;
$retrieve['MCQ_A'] = $a;
$retrieve['MCQ_B'] = $b;
$retrieve['MCQ_C'] = $c;
$retrieve['MCQ_D'] = $d;
$retrieve['MCQ_E'] = $e;
$retrieve['answer'] = $answer;
$retrieve['MCQ_correct'] = $correct;
}
?>
<form action='check.php' method='POST'>
<table>
<tr><td></td><td></td></tr>
<tr></tr>
<tr><td><input type='radio' name='group1' value='A' /></td><td> <?php echo $a; ?></td></tr>
<tr><td><input type='radio' name='group1' value='B' /></td><td> <?php echo $b; ?></td></tr>
<tr><td><input type='radio' name='group1' value='C' /></td><td> <?php echo $c; ?></td></tr>
<tr><td><input type='radio' name='group1' value='D' /></td><td> <?php echo $d; ?></td></tr>
<tr><td><input type='radio' name='group1' value='E' /></td><td> <?php echo $e; ?></td></tr>
<tr>
<?php
// sending the retrieved information from MYSQL via POST for use in check.php file
$qnumber;
$a;
$b;
$c;
$d;
$e;
$answer;
$correct;
?></tr>
<tr><td><input type="submit" value="Submit"></td></tr>
</table>
</form>
</body>
</html>