上传使用Python中SFTP文件，但如果路径不存在创建目录(Upload files using

我要上传文件与Python在远程服务器上。 我想先确认是否如果远程路径是真实存在的，如果实在不行，去创造。 在伪代码：

if(remote_path not exist):
    create_path(remote_path)
upload_file(local_file, remote_path)

我在想的paramiko中执行一个命令来创建路径（例如mkdir -p remote_path ）。 我想出了这个：

# I didn't test this code

import paramiko, sys

ssh = paramiko.SSHClient()
ssh.connect(myhost, 22, myusername, mypassword)
ssh.exec_command('mkdir -p ' + remote_path)
ssh.close

transport = paramiko.Transport((myhost, 22))
transport.connect(username = myusername, password = mypassword)

sftp = paramiko.SFTPClient.from_transport(transport)
sftp.put(local_path, remote_path)
sftp.close()

transport.close()

但这种方法不健全的对我好，因为我关闭连接，然后再次打开它。 有没有更好的办法做到这一点？

Answer 1:

SFTP支持常用的FTP命令（CHDIR，MKDIR，等...），所以使用这些：

sftp = paramiko.SFTPClient.from_transport(transport)
try:
    sftp.chdir(remote_path)  # Test if remote_path exists
except IOError:
    sftp.mkdir(remote_path)  # Create remote_path
    sftp.chdir(remote_path)
sftp.put(local_path, '.')    # At this point, you are in remote_path in either case
sftp.close()

---

要完全模拟mkdir -p ，就可以通过远程路径工作递归：

import os.path

def mkdir_p(sftp, remote_directory):
    """Change to this directory, recursively making new folders if needed.
    Returns True if any folders were created."""
    if remote_directory == '/':
        # absolute path so change directory to root
        sftp.chdir('/')
        return
    if remote_directory == '':
        # top-level relative directory must exist
        return
    try:
        sftp.chdir(remote_directory) # sub-directory exists
    except IOError:
        dirname, basename = os.path.split(remote_directory.rstrip('/'))
        mkdir_p(sftp, dirname) # make parent directories
        sftp.mkdir(basename) # sub-directory missing, so created it
        sftp.chdir(basename)
        return True

sftp = paramiko.SFTPClient.from_transport(transport)
mkdir_p(sftp, remote_path) 
sftp.put(local_path, '.')    # At this point, you are in remote_path
sftp.close()

当然，如果远程路径还包含一个远程文件名，则需要将其分离出来，正在传递的目录mkdir_p并用来代替文件名“” 在sftp.put。

Answer 2:

简单的东西稍微更可读的太

def mkdir_p(sftp, remote, is_dir=False):
    """
    emulates mkdir_p if required. 
    sftp - is a valid sftp object
    remote - remote path to create. 
    """
    dirs_ = []
    if is_dir:
        dir_ = remote
    else:
        dir_, basename = os.path.split(remote)
    while len(dir_) > 1:
        dirs_.append(dir_)
        dir_, _  = os.path.split(dir_)

    if len(dir_) == 1 and not dir_.startswith("/"): 
        dirs_.append(dir_) # For a remote path like y/x.txt 

    while len(dirs_):
        dir_ = dirs_.pop()
        try:
            sftp.stat(dir_)
        except:
            print "making ... dir",  dir_
            sftp.mkdir(dir_)

Answer 3:

有了这个今天做。 这里是我做到了。

def mkdir_p(sftp, remote_directory):
    dir_path = str()
    for dir_folder in remote_directory.split("/"):
        if dir_folder == "":
            continue
        dir_path += r"/{0}".format(dir_folder)
        try:
            sftp.listdir(dir_path)
        except IOError:
            sftp.mkdir(dir_path)

Answer 4:

的paramiko包含的mkdir功能：

http://paramiko-docs.readthedocs.org/en/latest/api/sftp.html#paramiko.sftp_si.SFTPServerInterface.mkdir

Answer 5:

假设SFTP操作是昂贵的，我会去的：

def sftp_mkdir_p(sftp, remote_directory):
    dirs_exist = remote_directory.split('/')
    dirs_make = []
    # find level where dir doesn't exist
    while len(dirs_exist) > 0:
        try:
            sftp.listdir('/'.join(dirs_exist))
            break
        except IOError:
            value = dirs_exist.pop()
            if value == '':
                continue
            dirs_make.append(value)
        else:
            return False
    # ...and create dirs starting from that level
    for mdir in dirs_make[::-1]:
        dirs_exist.append(mdir)
        sftp.mkdir('/'.join(dirs_exist))```

文章来源: Upload files using SFTP in Python, but create directories if path doesn't exist