C# Numeric Only TextBox Control [duplicate]

问题:

This question already has an answer here:

• numeric-only textbox as a control in Visual Studio toolbox 4 answers

I am using C#.NET 3.5, and I have a problem in my project. In C# Windows Application, I want to make a textbox to accept only numbers. If user try to enter characters message should be appear like "please enter numbers only", and in another textbox it has to accept valid email id message should appear when it is invalid. It has to show invalid user id.

回答1:

I suggest, you use the MaskedTextBox: http://msdn.microsoft.com/en-us/library/system.windows.forms.maskedtextbox.aspx

回答2:

From C#3.5 I assume you're using WPF.

Just make a two-way data binding from an integer property to your text-box. WPF will show the validation error for you automatically.

For the email case, make a two-way data binding from a string property that does Regexp validation in the setter and throw an Exception upon validation error.

Look up Binding on MSDN.

回答3:

use this code:

private void textBox1_KeyPress(object sender, KeyPressEventArgs e)
        {
            const char Delete = (char)8;
            e.Handled = !Char.IsDigit(e.KeyChar) && e.KeyChar != Delete;
        }

回答4:

You might want to try int.TryParse(string, out int) in the KeyPress(object, KeyPressEventArgs) event to check for numeric values. For the other problem you could use regular expressions instead.

回答5:

I used the TryParse that @fjdumont mentioned but in the validating event instead.

private void Number_Validating(object sender, CancelEventArgs e) {
    int val;
    TextBox tb = sender as TextBox;
    if (!int.TryParse(tb.Text, out val)) {
        MessageBox.Show(tb.Tag +  " must be numeric.");
        tb.Undo();
        e.Cancel = true;
    }
}

I attached this to two different text boxes with in my form initializing code.

    public Form1() {
        InitializeComponent();
        textBox1.Validating+=new CancelEventHandler(Number_Validating);
        textBox2.Validating+=new CancelEventHandler(Number_Validating);
    }

I also added the tb.Undo() to back out invalid changes.

回答6:

this way is right with me:

private void textboxNumberic_KeyPress(object sender, KeyPressEventArgs e)
{
     const char Delete = (char)8;
     e.Handled = !Char.IsDigit(e.KeyChar) && e.KeyChar != Delete;
}

回答7:

TRY THIS CODE

// Boolean flag used to determine when a character other than a number is entered.
private bool nonNumberEntered = false;
// Handle the KeyDown event to determine the type of character entered into the control.
private void textBox1_KeyDown(object sender, KeyEventArgs e)
{
    // Initialize the flag to false.
    nonNumberEntered = false;
    // Determine whether the keystroke is a number from the top of the keyboard.
    if (e.KeyCode < Keys.D0 || e.KeyCode > Keys.D9)
    {
        // Determine whether the keystroke is a number from the keypad.
        if (e.KeyCode < Keys.NumPad0 || e.KeyCode > Keys.NumPad9)
        {
            // Determine whether the keystroke is a backspace.
            if (e.KeyCode != Keys.Back)
            {
                // A non-numerical keystroke was pressed.
                // Set the flag to true and evaluate in KeyPress event.
                nonNumberEntered = true;
            }
        }
    }
}

private void textBox1_KeyPress(object sender, KeyPressEventArgs e)
{
    if (nonNumberEntered == true)
    {
       MessageBox.Show("Please enter number only..."); 
       e.Handled = true;
    }
}

Source is http://msdn.microsoft.com/en-us/library/system.windows.forms.control.keypress(v=VS.90).aspx

回答8:

You can check the Ascii value by e.keychar on KeyPress event of TextBox.

By checking the AscII value you can check for number or character.

Similarly you can write logic to check the Email ID.

回答9:

I think it will help you

<script type="text/javascript">
function isNumberKey(evt) {
    var charCode = (evt.which) ? evt.which : event.keyCode
    if (charCode > 32 && (charCode < 48 || charCode > 57) && (charCode != 45) && (charCode != 43) && (charCode != 40) && (charCode != 41))
        return false;

    return true;
}

回答10:

try
{
    int temp=Convert.ToInt32(TextBox1.Text);
}
catch(Exception h)
{
    MessageBox.Show("Please provide number only");
}