Get all child notes only one level lower from pare

2019-08-13 22:34发布

问题:

I write an automation testing software and have one problem now. In my actual native app I have a ListView like this here:

  • ListView
    • LinearLayout
      • LinearLayout
        • LinearLayout
      • TextView
    • LinearLayout
      • LinearLayout
    • LinearLayout
      • LinearLayout
    • LinearLayout
    • ...

... and more.

What I need and want is to get all one level lower LinearLayout (iterative ones, visible and non visible elements) from ListView:

ListView : {LinearLayout, LinearLayout, ...}

With that code I get all childs from ListView, but its to much for me:

listViewChildElements       = "[...]android.widget.ListView[1]//android.widget.LinearLayout";
app.getDriver().findElements(By.xpath(listViewChildElements));

In another post I see something with 'count', but I don't understand it.

Thanks for your help and nice to meet you.


With the help of @har07 I write one function, not best or finest solution and not finally, but the 1st step in the right lane:

    public static List<String> getAllViewElements(App app){
    int i = 0;

    List<String> writtenElementsByText = new ArrayList<String>();

    while(true){
        if(!writtenElementsByText.isEmpty()){
            String recentLastItem = writtenElementsByText.get(writtenElementsByText.size()-1);
            if(recentLastItem.equals("Alle Themen"))
                break;
            else
                app.getDriver().scrollTo(recentLastItem);
        }

        List<WebElement> tmp = app.getDriver().findElements(By.xpath(listViewChildElements));


        if(writtenElementsByText.isEmpty())
            for(WebElement e: tmp){
                writtenElementsByText.add(getTextFromElement(e));
            }
        else
            for(WebElement e: tmp){
                String activualElemenByText = getTextFromElement(e);
                if(!writtenElementsByText.contains(activualElemenByText))
                    writtenElementsByText.add(activualElemenByText);
            }
    }

    System.out.println(writtenElementsByText.size());
    for(String e: writtenElementsByText){
        System.out.println("\t-\t"+e);
    }
    return writtenElementsByText;
}

public static String getTextFromElement(WebElement element){
    return element.findElement(By.id(listViewChildElementTextID)).getText();
}

回答1:

If I understand the problem correctly, you want to use single slash (/) instead of double to get direct child element from a parent element :

listViewChildElements = "[...]android.widget.ListView[1]/android.widget.LinearLayout";
                                                        ^
                                                        notice that only one slash being 
                                                        used above

With that change, the XPath should now return LinearLayout that is direct child of the ListView[1].



回答2:

I hope the following piece of code helps :

 WebElement listViewElement = driver.findElement(<your ListView locator>);
 List<WebElement> listLinearLayoutChildren = listViewElement.findElements(By.className("android.widget.LinearLayout")); //All the linear layouts under ListView in one list
 listLinearLayoutChildren.get(index).<action>; //index of Nth linearlayout starting from 0 and <action> you want to perform


回答3:

One of the simplest way to do by setting Tag to each linearLayout. Now access linearlayout by view.findViewWithTag(index)