org.hibernate.HibernateException: Access to Dialec

2019-01-02 20:56发布

问题:

I am trying run a spring-boot application which uses hibernate via spring-jpa, but i am getting this error:

Caused by: org.hibernate.HibernateException: Access to DialectResolutionInfo cannot be null when 'hibernate.dialect' not set
        at org.hibernate.engine.jdbc.dialect.internal.DialectFactoryImpl.determineDialect(DialectFactoryImpl.java:104)
        at org.hibernate.engine.jdbc.dialect.internal.DialectFactoryImpl.buildDialect(DialectFactoryImpl.java:71)
        at org.hibernate.engine.jdbc.internal.JdbcServicesImpl.configure(JdbcServicesImpl.java:205)
        at org.hibernate.boot.registry.internal.StandardServiceRegistryImpl.configureService(StandardServiceRegistryImpl.java:111)
        at org.hibernate.service.internal.AbstractServiceRegistryImpl.initializeService(AbstractServiceRegistryImpl.java:234)
        at org.hibernate.service.internal.AbstractServiceRegistryImpl.getService(AbstractServiceRegistryImpl.java:206)
        at org.hibernate.cfg.Configuration.buildTypeRegistrations(Configuration.java:1885)
        at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1843)
        at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl$4.perform(EntityManagerFactoryBuilderImpl.java:850)
        at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl$4.perform(EntityManagerFactoryBuilderImpl.java:843)
        at org.hibernate.boot.registry.classloading.internal.ClassLoaderServiceImpl.withTccl(ClassLoaderServiceImpl.java:398)
        at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.build(EntityManagerFactoryBuilderImpl.java:842)
        at org.hibernate.jpa.HibernatePersistenceProvider.createContainerEntityManagerFactory(HibernatePersistenceProvider.java:152)
        at org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean.createNativeEntityManagerFactory(LocalContainerEntityManagerFactoryBean.java:336)
        at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.afterPropertiesSet(AbstractEntityManagerFactoryBean.java:318)
        at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1613)
        at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1550)
        ... 21 more

my pom.xml file is this:

<parent>
    <groupId>org.springframework.boot</groupId>
    <artifactId>spring-boot-starter-parent</artifactId>
    <version>1.1.8.RELEASE</version>
</parent>

<dependencies>
    <dependency>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-web</artifactId>
    </dependency>
    <dependency>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-actuator</artifactId>
    </dependency>
    <dependency>
        <groupId>org.springframework.security</groupId>
        <artifactId>spring-security-web</artifactId>
       </dependency>
    <dependency>
        <groupId>org.springframework.security</groupId>
        <artifactId>spring-security-config</artifactId>
    </dependency>
    <dependency>
        <groupId>org.springframework.security</groupId>
        <artifactId>spring-security-taglibs</artifactId>
    </dependency>
    <dependency>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-data-jpa</artifactId>
    </dependency>
    <dependency>
        <groupId>commons-dbcp</groupId>
        <artifactId>commons-dbcp</artifactId>
    </dependency>
</dependencies>

my hibernate configuration is that (the dialect configuration is in the last method from this class):

@Configuration
@EnableTransactionManagement
@ComponentScan({ "com.spring.app" })
public class HibernateConfig {

   @Bean
   public LocalSessionFactoryBean sessionFactory() {
      LocalSessionFactoryBean sessionFactory = new LocalSessionFactoryBean();

      sessionFactory.setDataSource(restDataSource());
      sessionFactory.setPackagesToScan(new String[] { "com.spring.app.model" });
      sessionFactory.setHibernateProperties(hibernateProperties());

      return sessionFactory;
   }

   @Bean
   public DataSource restDataSource() {
      BasicDataSource dataSource = new BasicDataSource();

      dataSource.setDriverClassName("org.postgresql.Driver");
      dataSource.setUrl("jdbc:postgresql://localhost:5432/teste?charSet=LATIN1");
      dataSource.setUsername("klebermo");
      dataSource.setPassword("123");

      return dataSource;
   }

   @Bean
   @Autowired
   public HibernateTransactionManager transactionManager(SessionFactory sessionFactory) {
      HibernateTransactionManager txManager = new HibernateTransactionManager();
      txManager.setSessionFactory(sessionFactory);
      return txManager;
   }

   @Bean
   public PersistenceExceptionTranslationPostProcessor exceptionTranslation() {
      return new PersistenceExceptionTranslationPostProcessor();
   }

   Properties hibernateProperties() {
      return new Properties() {
         /**
         * 
         */
        private static final long serialVersionUID = 1L;

        {
            setProperty("hibernate.hbm2ddl.auto", "create");
            setProperty("hibernate.show_sql", "false");
            setProperty("hibernate.dialect", "org.hibernate.dialect.PostgreSQLDialect");
         }
      };
   }
}

what I am doing wrong here?

回答1:

First remove all of your configuration Spring Boot will start it for you. If you really need a SessionFactory instead of an EntityManagerFactory add a HibernateJpaSessionFactoryBean.

Make sure you have an application.properties in your classpath and add the following properties.

spring.datasource.driverClassName=org.postgresql.Driver
spring.datasource.url=jdbc:postgresql://localhost:5432/teste?charSet=LATIN1
spring.datasource.username=klebermo
spring.datasource.password=123

spring.jpa.database-platform=org.hibernate.dialect.PostgreSQLDialect
spring.jpa.show-sql=false
spring.jpa.hibernate.ddl-auto=create

If you really need access to a SessionFactory and that is basically for the same datasource, then you can do the following (which is also docmented here although for XML, not JavaConfig).

@Configuration        
public class HibernateConfig {

    @Bean
    public HibernateJpaSessionFactoryBean sessionFactory(EntityManagerFactory emf) {
         HibernateJpaSessionFactoryBean factory = new HibernateJpaSessionFactoryBean();
         factory.setEntityManagerFactory(emf);
         return factory;
    }
}

That way you have both an EntityManagerFactory and a SessionFactory.

Assuming you have a class with a main method with @EnableAutoConfiguration you don't need the @EnableTransactionManagement annotation, as that will be enabled by Spring Boot for you. A basic application class in the com.spring.app package should be enough.

@Configuration
@EnableAutoConfiguration
@ComponentScan
public class Application {


    public static void main(String[] args) throws Exception {
        SpringApplication.run(Application.class, args);
    }

} 

Something like that should be enough to have all your classes (including entities and Spring Data based repositories) detected.

I would also suggest removing the commons-dbcp dependency as that would allow Spring Boot to configure the faster and more robust HikariCP implementation.



回答2:

I was facing a similar problem when starting up the application (using Spring Boot) with the database server down.

Hibernate can determine the correct dialect to use automatically, but in order to do this, it needs a live connection to the database.



回答3:

I got this error when my database was not created. After creating the DB manually, it worked fine.



回答4:

I also faced similar issue. But, it was due to the invalid password provided. Also, I would like to say your code seems to be old style code using spring. You already mentioned that you are using spring boot, which means most of the things will be auto configured for you. hibernate dialect will be auto selected based on the DB driver available on the classpath along with valid credentials which can be used to test the connection properly. It there is any issue with the connection you will again face the same error. only 3 properties needed in application.properties

# Replace with your connection string
spring.datasource.url=jdbc:mysql://localhost:3306/pdb1

# Replace with your credentials
spring.datasource.username=root
spring.datasource.password=


回答5:

add spring.jpa.properties.hibernate.dialect = org.hibernate.dialect.MySQLDialect in application.properties file



回答6:

I ran into the same problem and my issue was that the DB I was trying to connect to didn't exist.

I created the DB, verified the URL/connection string and reran and everything worked as expected.



回答7:

this is happening because your code is not bale to connect the database. Make sure you have mysql driver and username, password correct.



回答8:

Make sure your application.properties has all correct info: (I changed my db port from 8889 to 3306 it worked)

 db.url: jdbc:mysql://localhost:3306/test


回答9:

In my case the user could not connect to the database. If will have same issue if the log contains a warning just before the exception:

WARN HHH000342: Could not obtain connection to query metadata : Login failed for user 'my_user'.


回答10:

Make sure you have your database in your pom like OP did. That was my problem.



回答11:

My problem was that embedded database was already connected. close connection



回答12:

I had the same issue and it was caused by being unable to connect to the database instance. Look for hibernate error HHH000342 in the log above that error, it should give you an idea to where the db connection is failing (incorrect username/pass, url, etc.)



回答13:

If you are using this line:

sessionFactory.getHibernateProperties().put("hibernate.dialect", env.getProperty("hibernate.dialect"));

make sure that env.getProperty("hibernate.dialect") is not null.



回答14:

This happened to me because I hadn't added the conf.configure(); before beginning the session:

Configuration conf = new Configuration();
conf.configure();


回答15:

Make sure that you have enter valid detail in application.properties and whether your database server is available. As a example when you are connecting with MySQL check whether XAMPP is running properly.



回答16:

I faced the same issue: The db I was trying to connect did not exist. I used jpa.database=default (which I guess means it will try to connect to the database and then auto select the dialect). Once I started the database, it worked fine without any change.



回答17:

Same but in a JBoss WildFly AS.

Solved with properties in my META-INF/persistence.xml

<properties>
            <property name="hibernate.transaction.jta.platform"
                value="org.hibernate.service.jta.platform.internal.JBossAppServerJtaPlatform" />
            <property name="spring.jpa.database-platform" value="org.hibernate.dialect.PostgreSQLDialect" />
            <property name="spring.jpa.show-sql" value="false" />
</properties>


回答18:

For those working with AWS MySQL RDS, it may occur when you are unable to connect to the database. Go to AWS Security Groups setting for MySQL RDS and edit the inbound IP rule by refreshing MyIP.

I faced this issue and doing above got the problem fixed for me.



回答19:

I faced this issue due to Mysql 8.0.11 version reverting back to 5.7 solved for me



回答20:

I had the same error after using the hibernate code generation

https://www.mkyong.com/hibernate/how-to-generate-code-with-hibernate-tools/

then the hibernate.cfg.xml was created in /src/main/java but without the connection parameters after removing it - my problem was solved



回答21:

I got this issue when Eclipse was unable to find the JDBC driver. Had to do a gradle refresh from the eclipse to get this work.



回答22:

In spring boot for jpa java config you need to extend JpaBaseConfiguration and implement it's abstract methods.

@Configuration
public class JpaConfig extends JpaBaseConfiguration {

    @Override
    protected AbstractJpaVendorAdapter createJpaVendorAdapter() {
        final HibernateJpaVendorAdapter vendorAdapter = new HibernateJpaVendorAdapter();
        return vendorAdapter;
    }

    @Override
    protected Map<String, Object> getVendorProperties() {
        Map<String, Object> properties = new HashMap<>();
        properties.put("hibernate.dialect", "org.hibernate.dialect.PostgreSQLDialect");
    }

}


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