Let's suppose that I have a dataframe with two columns in pandas
which resembles the following one:
text label
0 This restaurant was amazing Positive
1 The food was served cold Negative
2 The waiter was a bit rude Negative
3 I love the view from its balcony Positive
and then I am using TfidfVectorizer
from sklearn
on this dataset.
What is the most efficient way to find the top n in terms of TF-IDF score vocabulary per class?
Apparently, my actual dataframe consists of many more rows of data than the 4 above.
The point of my post to find the code which works for any dataframe which resembles the one above; either 4-rows dataframe or 1M-rows dataframe.
I think that my post is related quite a lot to the following posts:
- Scikit Learn TfidfVectorizer : How to get top n terms with highest tf-idf score
- How to see top n entries of term-document matrix after tfidf in scikit-learn
In the following, you can find a piece of code I wrote more than three years ago for a similar purpose. I'm not sure if this is the most efficient way of doing what you're going to do, but as far as I remember, it worked for me.
# X: data points
# y: targets (data points` label)
# vectorizer: TFIDF vectorizer created by sklearn
# n: number of features that we want to list for each class
# target_list: the list of all unique labels (for example, in my case I have two labels: 1 and -1 and target_list = [1, -1])
# --------------------------------------------
# splitting X vectors based on target classes
for label in target_list:
# listing the most important words in each class
indices = []
current_dict = {}
# finding indices the of rows (data points) for the current class
for i in range(0, len(X.toarray())):
if y[i] == label:
indices.append(i)
# get rows of the current class from tf-idf vectors matrix and calculating the mean of features values
vectors = np.mean(X[indices, :], axis=0)
# creating a dictionary of features with their corresponding values
for i in range(0, X.shape[1]):
current_dict[X.indices[i]] = vectors.item((0, i))
# sorting the dictionary based on values
sorted_dict = sorted(current_dict.items(), key=operator.itemgetter(1), reverse=True)
# printing the features textual and numeric values
index = 1
for element in sorted_dict:
for key_, value_ in vectorizer.vocabulary_.items():
if element[0] == value_:
print(str(index) + "\t" + str(key_) + "\t" + str(element[1]))
index += 1
if index == n:
break
else:
continue
break